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Convert rows to columns based on key and count

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# 1  
Old 01-13-2016
Convert rows to columns based on key and count

I am having requirement to convert rows to columns
Input is:
key ,count, id1, pulse1, id2, pulse2 ,id3, pulse3 
12, 2 , 14 , 56 , 15, 65
13, 3, 12, 32, 14, 23, 18, 54
22, 1 , 32, 42

Expected Out put:
key, id,pulse
12, 14, 56
12, 15, 65
13 ,12, 32
13, 14 ,23
13, 18 ,54
22 ,32, 42

Explanation: based on "count" , id and pulse sets will be repeated "count" number of times
I need a O/p which should contain key,id,pulse in a normalized was as shown above.your help is appreciated

Moderator's Comments:
Mod Comment edit by bakunin: PLEASE! I tried to clean out all the FONT- and what-not tags you used and ended up writing a script because it took too long to do it by hand. The only tag you should have used - CODE-tags - you didn't use at all. Spare me this and we will get along just nicely. Thank you!

Last edited by bakunin; 01-13-2016 at 06:55 PM..
# 2  
Old 01-13-2016
Have a look at the bottom of this page, where you will find half a dozen threads dealing with exactly this. "Convert Rows to Columns" has been asked and answered so often we could fill a separate board with it.

Against popular belief it is NOT FORBIDDEN to use the search function!

I hope this helps.

# 3  
Old 01-14-2016
I checked the following links, but I was not successful in converting rows to columns dynamically based on count. I am not very familiar with unix scripting ,I usually pick the unix commands through forums.
# 4  
Old 01-14-2016
Wouldn't it be nice to develop some personal skills?
Anyhow, try
awk '
NR == 1 {FS = OFS = ","
         print "key, id,pulse"
        {gsub(/ ,/,",")
         for (i=3; i<=NF; i+=2) print $1, $i, $(i+1)
' file
key, id,pulse
12, 14, 56
12, 15, 65
13, 12, 32
13, 14, 23
13, 18, 54
22, 32, 42

As the commas in both sample input and output seem randomly seeded, I took the freedom to slightly align them...
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