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Too many arguments

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# 1  
Old 12-22-2015
Too many arguments
because it gives me this error if?

Code:
while read linea
     do
       #echo "Archivos Entrada: $linea"
       largo=`awk '{print length($linea)}'`
       echo "largo : $largo "

       if [ $largo == 171  ]; then  #Here's the problem, I take this line and it works
         echo "a es igual a 1"
       fi

     done <  ${PATH_DAT}/$ArchPro #while read linea

# 2  
Old 12-22-2015
Your first problem is in
Code:
   largo=`awk '{print length($linea)}'`

$linea is not substituted because it is within 'ticks'.
And awk wants to read from stdin.
As a result $largo is empty, leading to your second problem (that should say error in [ ]).
An improvement is
Code:
   largo=`echo "$linea" | awk '{print length($0)}'`

But this can be done with a shell builtin
Code:
   largo=${#linea}

This User Gave Thanks to MadeInGermany For This Post:
tricampeon81
# 3  
Old 12-22-2015
perfect !!!!
works perfect with this was what I needed

Code:
largo=${#linea}

# 4  
Old 12-23-2015
Actually, there's no need for a variable unless you need the length again later on:
Code:
if [ ${#linea} -eq 171  ]; then ...

Please note that integer comparison is done preferably with-eq although not needed here.
Last edited by RudiC; 12-23-2015 at 11:44 AM.. Reason: typo
This User Gave Thanks to RudiC For This Post:
tricampeon81
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