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Grep - build character range with octal or hexa representation

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# 1  
Old 12-18-2015
Grep - build character range with octal or hexa representation
Hello

I would like to make a character range like that :
Code:
echo "ABCDEF+1234" | grep -E '[\x26-\x40]'

or
Code:
echo "ABCDEF+1234" | grep -E '[\046-\100]'

or
Code:
echo "ABCDEF+1234" | grep -E '[&-@]'

Which should works on linux with english language
And works also on linux with french language ( english install and after add french )
On my second laptop ( french ) I got this error :
Code:
grep: end of interval invalid

but its works on my server (english)
# 2  
Old 12-18-2015
Would this help?
Code:
echo "ABCDEF+1234" | grep -E "[\x26-\x40]"
grep: Invalid range end
echo "ABCDEF+1234" | LC_ALL=C grep -E "[\x26-\x40]"
ABCDEF+1234

---------- Post updated at 17:49 ---------- Previous update was at 17:40 ----------

And this would correctly produce the chars equivalent to the hex codes:
Code:
echo "ABCDEF+1234" | LC_ALL=C grep -E "["$'\x26'-$'\x40'"]"
+ grep -E '[&-@]'
ABCDEF+1234

This User Gave Thanks to RudiC For This Post:
jcdole
# 3  
Old 12-18-2015
Quote:
Originally Posted by RudiC
Would this help?
Code:
echo "ABCDEF+1234" | grep -E "[\x26-\x40]"
grep: Invalid range end
echo "ABCDEF+1234" | LC_ALL=C grep -E "[\x26-\x40]"
ABCDEF+1234

---------- Post updated at 17:49 ---------- Previous update was at 17:40 ----------

And this would correctly produce the chars equivalent to the hex codes:
Code:
echo "ABCDEF+1234" | LC_ALL=C grep -E "["$'\x26'-$'\x40'"]"
+ grep -E '[&-@]'
ABCDEF+1234

Is there a way to put some macro LC_ALL=C at the beginning of the script if language is not English and remove it before the grep pipe
# 4  
Old 12-18-2015
Sorry?
# 5  
Old 12-18-2015
I got it
Put that at the beginning of the script.
Code:
export LC_ALL=C

Valid only for the script

Thank you very much for helping
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