Pattern match and replace indirect directory reference using sed


 
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# 1  
Old 12-10-2015
Pattern match and replace indirect directory reference using sed

Hi,

I need a ksh script to replace indirect directory references in an .ini file with a env variable using sed or awk.

The .ini file is for example as such:

Code:
A=..
B=../
C=../..
D=../../
E=../bin
F=../../bin
G=../../bin/xml
H=../../bin/xml/

Need to replace an instance of .. or ../.. with %HOME%

so

Code:
A=%HOME%
B=%HOME%/
C=%HOME%
D=%HOME%/
E=%HOME%/bin
F=%HOME%/bin
G=%HOME%/bin/xml
H=%HOME%/bin/xml/


Last edited by andyatit; 12-10-2015 at 10:20 AM.. Reason: Add shell
# 2  
Old 12-10-2015
Well, try

Code:
sed -r 's#\.\.(/\.\.)*#%HOME%#' file

-Ranga
This User Gave Thanks to rangarasan For This Post:
# 3  
Old 12-10-2015
Unix sed needs
Code:
sed 's#\.\.\(/\.\.\)\{0,1\}#%HOME%#' file

This User Gave Thanks to MadeInGermany For This Post:
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