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Basic FOR loop with break

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# 1  
Old 11-17-2015
Basic FOR loop with break
Oracle Linux : 6.4/bash shell

In the below I want to break out of the loop when it enters the 5th iteration.

Code:
#!/bin/bash
for i in 1 2 3 4 5 6
do
 echo "$i"
	if	[ $i -eq 5 ]
		echo "Oh Nooo... i = $i. I need to stop the iteration and jump out of the loop"
		then break
	fi
done


But, it only iterates once. Why ?

Output:

Code:
$ ./breakTest.sh
1
Oh Nooo... i = 1. I need to stop the iteration and jump out of the loop
$

# 2  
Old 11-18-2015
Code:
if [ $i -eq 5 ]
   then
   echo "Oh Nooo....etc"
   break
fi

This User Gave Thanks to cjcox For This Post:
John K
# 3  
Old 11-18-2015
Thank you cjcox. I placed then keyword in the wrong place Smilie
# 4  
Old 11-18-2015
Computer src from [url]http://tldp.org/HOWTO/Bash-Prog-Intro-HOWTO-7.html[/url]
You can use a WHILE loop like this ...
Code:
COUNTER=0; while [  $COUNTER -lt 6 ]; do; echo "Oh Nooo... The counter is $COUNTER. I need to stop the iteration and jump out of the loop"; let COUNTER=COUNTER+1 ; done

or an UNTIL loop like this ...
Code:
COUNTER=5; until [  $COUNTER -eq 4 ]; do echo "Oh Nooo... The counter is $COUNTER. I need to stop the iteration and jump out of the loop" ; let COUNTER-=1; done

Last edited by Don Cragun; 11-18-2015 at 09:10 PM.. Reason: Change ICODE tags to CODE tags.
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