Find Default user


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# 1  
Find Default user

All,

Working in Kubuntu 14.04

I know I can find the default user line using the cmd from bash:

Code:
cat /etc/passwd | grep 1000

What I get is:

Code:
user:x:1000:1000:User Name,,,:/home/user:/bin/bash

How do I extract to get:

Code:
myuser=$user
myhome=$homdir

All help appreciated!

Thanks!

OMR

Last edited by Don Cragun; 11-09-2015 at 04:37 PM.. Reason: Add CODE tags.
# 2  
See if any of these will get you going:
Code:
awk -F":" '/1000/ {print $1, $6}' /etc/passwd

or:
Code:
awk -F":" '$3=="1000" {print $1, $6}' /etc/passwd

By the way
Code:
cat /etc/passwd | grep 1000

is like eating macaronis using a fork first to load into a spoon.
grep can read files by itself
Code:
grep 1000 /etc/passwd


Last edited by Aia; 11-09-2015 at 04:48 PM..
# 3  
Expanding on what Aia said to get those values assigned to the desired variables:
Code:
read myuser myhome <<< $(awk -F":" '$3=="1000" {print $1, $6}' /etc/passwd)

# 4  
pure bash:
Code:
 while IFS=":" read user _ userid _ _ homedir _; do [ $userid -eq 1000 ] && break; done < /etc/passwd

or
Code:
IFS=":" read user _ userid _ _ homedir _ <<< $(grep ".*:.*:1000:" /etc/passwd)

This is not false positive proof, though.
# 5  
Rudi, your second solution must have the here-string in quotes.
Just like the following
Code:
IFS=":" read myuser x x x x myhome x <<< "`getent passwd 1000`"

Otherwise special characters can spoil it.
And bash seems to have a parsing problem...?
# 6  
Works for my bash. What special chars could spoil it? The here string would supply one single (hopefully) line that would be read into the variables.
# 7  
I get this:
Code:
% cat passwd
root:x:0:0:Super-User:/:/bin/sh
user:x:1000:0:Super-User:/:/bin/sh
% IFS=":" read user _ userid _ _ homedir _ <<< $(grep ".*:.*:1000:" passwd); echo $user; echo $userid
user x 1000 0 Super-User / /bin/sh

% IFS=":" read user _ userid _ _ homedir _ <<< "$(grep ".*:.*:1000:" passwd)"; echo $user; echo $userid
user
1000
% echo $BASH_VERSION
3.2.57(1)-release
%

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