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Pattern search and modify the values

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# 1  
Old 11-02-2015
Pattern search and modify the values
I have one file and the file may contain 500 to 15,000 records. I need to search pattern ^F509= and then increment the corresponding value by one and print the entire line.
Please note that Its not a fixed length file. Can anyone please help?



ex:
Code:
^F509=204656
     ^F509=204656
     ^F509=204656

The value should be
Code:
^F509=204656
                              ^F509=204657
                              ^F509=204658

Please refer the attached input and output file.
inputfile.txt (225 Bytes) 
outputfile.txt (225 Bytes) 
Last edited by Scrutinizer; 11-02-2015 at 02:27 PM.. Reason: code tags not icode
# 2  
Old 11-02-2015
What if that field's numbers are NOT equal?
Code:
^F509=204656
^F509=209996
^F509=146569

# 3  
Old 11-02-2015
Try something like:
Code:
awk '$2~/^F509=/{split($2,F,/=/); if(n=="")n=F[2]; $2=F[1]"="n++}1' FS=^ OFS=^ file

Last edited by Scrutinizer; 11-02-2015 at 02:50 PM..
# 4  
Old 11-02-2015
Quote:
Originally Posted by RudiC
What if that field's numbers are NOT equal?
Code:
^F509=204656
^F509=209996
^F509=146569

The field numbers are always equal.

---------- Post updated at 03:12 PM ---------- Previous update was at 03:10 PM ----------

Quote:
Originally Posted by Scrutinizer
Try something like:
Code:
awk '$2~/^F509=/{split($2,F,/=/); if(n=="")n=F[2]; $2=F[1]"="n++}1' FS=^ OFS=^ file

I'm not sure whether this logic will work because ^F509 can come anywhere in the file (not $2) .
# 5  
Old 11-02-2015
Try
Code:
awk 'match ($0, /\^F509[^^]*/) && !L {L=1; m=n=substr ($0, RSTART+6, RLENGTH-6)} {sub (m, n++)}1' /tmp/inputfile.txt
DATAk(jdkfjk)09335"mk"8789eetet8766^F509=204657^F321=khfjfd^F870=76547854
DATAk(jdkfjk)09335"mk"8789rtrtr87f6^F509=204658^F321=khfdfdf^F870=76547854
DATAk(jdkfjk)09335"mk"878dg98fdd766^F509=204659^F321=khddjfd^F870=76547854

This User Gave Thanks to RudiC For This Post:
vinus
# 6  
Old 11-03-2015
Quote:
Originally Posted by vinus
The field numbers are always equal.

---------- Post updated at 03:12 PM ---------- Previous update was at 03:10 PM ----------



I'm not sure whether this logic will work because ^F509 can come anywhere in the file (not $2) .
Ok, adjusted to any field:
Code:
awk '{for(i=1; i<=NF; i++) if($i~/^F509=/){split($i,F,/=/); if(n=="")n=F[2]; $i=F[1]"="n++}}1' FS=^ OFS=^ file

---
Quote:
Originally Posted by RudiC
Try
Code:
awk 'match ($0, /\^F509[^^]*/) && !L {L=1; m=n=substr ($0, RSTART+6, RLENGTH-6)} {sub (m, n++)}1' /tmp/inputfile.txt
[ .. ]

This will fail if there is a line that happens to have the same sequence of numbers before the F509 field. Then sub (m, n++) will substitute those numbers instead of those in the F509 field...
Last edited by Scrutinizer; 11-03-2015 at 12:19 AM..
This User Gave Thanks to Scrutinizer For This Post:
vinus
# 7  
Old 11-03-2015
Hello Forum!

Back after a long absence. Awk is fun and I needed to flex my brain cells. Here is mine:

Code:
awk '$2~/^F509/{i++; split($2,a,"="); $2=a[1]"="a[2]+i}1' FS=^ OFS=^ file

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