Remove extension in loop


 
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# 8  
Old 10-26-2015
Are you sure that it's interpreted by bash? Or is it part of a script that has a #!sh shebang?
# 9  
Old 10-26-2015
A shell that does not understand this would throw an error.
--
In case you have two or more extensions, e.g. file1.txt.txt, then you get
Code:
echo ${file%.*}
file1.txt

Perhaps you need
Code:
echo ${file%%.*}
file1

# 10  
Old 10-27-2015
Sorry all my shell is
Code:
#!sh

Thanks made in Germany but your suggestion doesn't work!
# 11  
Old 10-27-2015
Please run the script with the -x option set and post the output.
# 12  
Old 10-27-2015
Really sorry guys the solution of MadeinGermany works fine...I had a my mistake!

Sorry for annoying you!

Thanks

Giuliano
This User Gave Thanks to giuliangiuseppe For This Post:
# 13  
Old 10-27-2015
No trouble, though I'm left curious what the issue was Smilie
# 14  
Old 10-27-2015
my fault..

Usage is

Code:
command [options] <input> <ouput.prefix>

my command for this site was was

Code:
for file in /path/to/*.txt
do command -input $file -output "${file%.*}"_sorted.txt
done

My real command was

Code:
for file in /path/to/*.txt
do command $file -o "${file%.*}"_sorted.txt
done

That was because I though was more clear specify INPUT and OUTPUT for you.
BUT
My mistake was to think that
Code:
-o

was
Code:
output

when instead is
Code:
final output to stdout

well that was do not know how it matter..
hope that my awful explanation is clear.. better I go home now!

still sorry for my mistake next time i'll read carefully the options!

best
This User Gave Thanks to giuliangiuseppe For This Post:
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