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awk command not getting executed in shell script

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# 1  
Old 10-23-2015
awk command not getting executed in shell script
I am able to execute awk command from shell prompt. but the same command is not getting executed when written and run in a bash script

the command from bash cmd prompt.
Code:
awk '/world/{for (i=2; i<NF; i++) printf $i " "; print $NF}1' myfile >tmp$$ ; mv tmp$$ myfile

file:
#  hello world my friend
# this is a beautiful place
$ mary had a little lamb
# jhony jhony yes papa
 
OP
hello world my friend
# this is a beautiful place
$ mary had a little lamb
# jhony jhony yes papa

But the same thing on trying with a bash script, no output is observed
script
Code:
#!/bin/bash
#!/usr/bin/awk 
NAME="world"
awk '/$NAME/{for (i=2; i<NF; i++) printf $i " "; print $NF}1' myfile >tmp$$ ; mv tmp$$ myfile

# 2  
Old 10-23-2015
There's two reasons that construct doesn't work - neither within nor without a script:
- within single quotes shell expansion is not performed - $NAME is taken literally.
- awk interprets anything between / as a regex constant - again, $NAME will be taken literally.

Use the -v option to awk to hand over parameters, and use the match function in lieu of the /... /

On top, only the shebang in the first line will be interpreted.
# 3  
Old 10-23-2015
Hello Ashima,

In awk value of variables dosn't work like shell ones. Could you please try following and let me know if this helps you.
Code:
#!/bin/bash
NAME="world"
awk -vname=$NAME  '{if($0 ~ /name/){for (i=2; i<NF; i++) printf $i " "; print $NF}}1' myfile >tmp$$ ; mv tmp$$ myfile

Let me know if you have any queries.


Thanks,
R. Singh
Last edited by RavinderSingh13; 10-23-2015 at 11:43 AM.. Reason: Edited the code by adding if condition. Thanks to vgresh.
# 4  
Old 10-23-2015
Quote:
Originally Posted by RavinderSingh13
Hello Ashima,

In awk value of variables dosn't work like shell ones. Could you please try following and let me know if this helps you.
Code:
#!/bin/bash
NAME="world"
awk -vname=$NAME  '/name/{for (i=2; i<NF; i++) printf $i " "; print $NF}1' myfile >tmp$$ ; mv tmp$$ myfile

Let me know if you have any queries.


Thanks,
R. Singh
no, this won't work either for the reasons RudiC explained above.
Code:
#!/bin/bash
NAME="world"
awk -vname=$NAME  '$0 ~ name{for (i=2; i<NF; i++) printf $i " "; print $NF}1' myfile >tmp$$ ; mv tmp$$ myfile

This User Gave Thanks to vgersh99 For This Post:
RavinderSingh13
# 5  
Old 10-23-2015
Code:
awk '/world/{for (i=2; i<NF; i++) printf $i " "; print $NF}1' myfile >tmp$$ ; mv tmp$$ myfile

I am afraid that the above command will never produce what you said, but rather the following:

Code:
hello world my friend
#  hello world my friend
# this is a beautiful place
$ mary had a little lamb
# jhony jhony yes papa

If your intention is to remove the comment and the spaces in front of any sentence that has the word `world', perhaps sed would be a bit more suitable for it.

Code:
#!/bin/bash
NAME="world"
sed "/$NAME/ s/^#[[:blank:]]*//" myfile >tmp$$
mv tmp$$ myfile

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