Shell Programming and Scripting

grep [0-9] [0-9] [0-9] [0-9]2009 infile
or
grep 09[0-9] [0-9] [0-9] [0-9] [0-9] infile

$ perl -ne 's/[^\: \/\d\n]//g; print "Result=" . join(" ", split), "\n"' file
Result=090326 20:00 20090327 08:00
Result=25/03/2009 1524 27032009 17:30

$ echo "Today 090326 she left the office at 20:00, and tomorrow 20090327 will come at 08:00" |sed 's/[a-z]//g'|sed 's/[A-Z]//g'
 090326      20:00,   20090327    08:00

cat file sed s/[0-9][0-9]//g

> sample="Day_01 090326 she left the office at 20:00, and tomorrow 20090327 will come at 08:00 "
> sample2=`echo $sample | tr " " "\n" | egrep -e "[0-9][0-9][0-9:]" | tr "\n" " " | tr -d ","`
> echo $sample2
090326 20:00 20090327 08:00

echo "Day_01 090326 she left the office at 20:00, and tomorrow 20090327 will come at 08:00"|sed 's/[a-z]//g'|sed 's/[A-Z]_\([0-9]\{2\}\)//g'
 090326      20:00,   20090327    08:00

 
cat Infile | sed 's/[A-Za-z:_,-.=()\/]//g'