Shell Programming and Scripting

Hi
Need help for below coding scenario.

I have a file with say 4 lines as below.

Code:

DEFINE JOB TPT_LOAD_INTO_EMP_DET
( TDPID = @TPT_TDSERVER , USERNAME = @TPT_TDUSER ) ;
( 'DROP TABLE '||@TPT_WRKDB ||'.LOG_'||@TPT_TGT ||' ; ') ,
SELECT * FROM OPERATOR (FILE_READER[1]) ; ) ;

Now I want to find all those words separately from every line starting with "@" and ending with " " and write them in a file

Example: my out file should contain

Code:

TPT_TDSERVER
TPT_TDUSER
TPT_WRKDB
TPT_TGT

Please help me as it is urgent. I tried to achieve this using grep, awk and sed but could not reach to the expected result.

Thanks in advance
Santanu

Moderator's Comments:

edit by bakunin: please use CODE-tags as required by the rules. Thank you.

Please use code tags as required by forum rules!

And, show us your vain attempts so we can help.

A small sed-loop chopping off one word after the other:

Code:

sed -n ':loop
/@/ {
  s/^[^@]*//
  s/^@\([^ ][^ ]*\) /\1\n/
  P
  D
  b loop
}' /path/to/your/file

I hope this helps.

bakunin

Try:

Code:

awk 'NR>1{print $1}' RS=@ file>newfile

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Try also

Code:

grep -o "@[^ ]* " file
@TPT_TDSERVER 
@TPT_TDUSER 
@TPT_WRKDB 
@TPT_TGT

If the "@" needs to go away, pipe it through tr -d @

Thanks to all of you. What I tried initially was ,

1. grep -o '@' <full file name>
2. grep "@" <full file name> | awk -F 'FS' 'BEGIN{FS="@"}{for (i=1;i<=NF;i++) {printf $i FS}}'

and in sed it was not so handy.

I was not able to get the result before which I am getting now after help from you guys. Thanks again.

Santanu