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Check if a string exists in a file

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# 1  
Old 07-23-2015
Check if a string exists in a file
bash in RHEL 6.3

I have these 2 files with strings.

Code:
$ cat someStrings.txt
LOGICAL1
HUNGARY2
PENGUIN2
MOBILE
GUITAR1
MOUSE1
$

Code:
$ cat checkIF.txt
PENGUIN
MOBILE
$

I need to search for strings in someStrings.txt file that matches the patterns in checkIF.txt file.
The strings in someStrings.txt sometimes end with a number . But, during pattern match, this number should be ignored.
If there is at least 1 match, just print PENGUIN exists in someStrings.txt file.

Logic will look like

Code:
if
grep -c PENGUIN someStrings.txt > 0
then print 'PENGUIN exists in someStrings.txt file'
then proceed with pattern search in the file
fi

So, with the sample data given above, my expected output will be

PENGUIN exists in someStrings.txt file ( PENGUIN2 exists in someStrings.txt file is fine too )
MOBILE exists in someStrings.txt file

Any idea how I could do this ?
# 2  
Old 07-23-2015
Hello kraljic,

Could you please try following and let me know if this helps.
Code:
awk 'FNR==NR{gsub(/[[:digit:]]/,X,$0);A[$0];next} ($1 in A){print $1 " exists in file " ARGV[1]}' somestrings.txt checkIF.txt

Output will be as follows.
Code:
PENGUIN exists in file somestrings.txt
MOBILE exists in file somestrings.txt

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
kraljic
# 3  
Old 07-23-2015
If the -H option for grep is available on your system, try
Code:
grep -Hf checkIF.txt someStrings.txt

This User Gave Thanks to RudiC For This Post:
kraljic
# 4  
Old 07-23-2015
Thank you Ravinder, Rudic

One last question : How can I grep only those lines that end with a number ?
ie. in the below file, all lines except the string MOBILE should be returned.

Code:
$ cat someStrings.txt
LOGICAL1
HUNGARY2
PENGUIN2
MOBILE
GUITAR1
MOUSE1

$
# 5  
Old 07-23-2015
Hello kraljic,

Could you please try following and let me know if this helps. Sorry didn't test it though because I am travelling as of now, hope this helps.
Code:
awk '($NF ~ /[[:digit:]]$/)' Input_file

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
kraljic
# 6  
Old 07-23-2015
Or:
Code:
grep '[[:digit:]]$' someStrings.txt

This User Gave Thanks to Don Cragun For This Post:
kraljic
# 7  
Old 07-23-2015
Quote:
Originally Posted by RavinderSingh13
Hello kraljic,

Could you please try following and let me know if this helps.
Code:
awk 'FNR==NR{gsub(/[[:digit:]]/,X,$0);A[$0];next} ($1 in A){print $1 " exists in file " ARGV[1]}' somestrings.txt checkIF.txt

Output will be as follows.
Code:
PENGUIN exists in file somestrings.txt
MOBILE exists in file somestrings.txt

Thanks,
R. Singh
Note: Even though this will work with the sample at hand, since it is only the last digits that need to be ignored, an anchor ($)should be used. Also, to ignore any kind of spaces and make it more robust, $1 should be used rather than $0, so instead of
Code:
gsub(/[[:digit:]]/,X,$0)

try:
Code:
sub(/[[:digit:]]+$/,X,$1)

This User Gave Thanks to Scrutinizer For This Post:
kraljic
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