Sed: find and replace backwards, until string

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# 1  
Old 07-22-2015
Sed: find and replace backwards, until string

Some help please:
Need to find string ||(everything in front of it)B0300|| and replace it with ||0|| globally



1507200053342 may differ each time.

sed 's/dont know how to do this:-)B0300||/||0||/g'

Thank you in advance for any help
# 2  
Old 07-22-2015
Hello drbiloukos,

Please use code tags as per forum rules for inputs/codes which you are using for your posts. Could you please use following and let me know if this helps you.
 echo "16112121||||0||0||0||0||0||52||52||0||0||0||0||1507200053342B0300||1507200053342B0300||0||0||0||0700" | awk -F"|" '{for(i=1;i<=NF;i++){if($i ~ /B0300/){$i=0};A=A?A OFS $i:$i}} END{print A}' OFS="|"

Output will be as follows.

R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
# 3  
Old 07-22-2015
Apologies I forgot tags. It works as expected. Many thanks.
# 4  
Old 07-22-2015
sed 's#\([^|]*B0300\)\([|]\)#0\2#g' filename

This User Gave Thanks to Yoda For This Post:
# 5  
Old 07-22-2015
awk 'gsub(/[^|]*B0300\|/,"0|")' file

This User Gave Thanks to RudiC For This Post:
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