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Insert tags which matches the pattern

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# 1  
Old 07-14-2015
Insert tags which matches the pattern
Hi Guys,

How to achieve this in awk or sed:
Patterns: A.B. No. T-8346 or A.B. No. T-8xxx
will look like this:
Patterns: A.B. No. T-8346<br> or A.B. No. T-8xxx<br>

#cat file.txt
Code:
 [A.B. No. T-8346, January 01, 2015 ]
JHON VS. PETER, AGOO PET.

How Old Are You

the file will look like this:
Code:
 A.B. No. T-8346<br> January 01, 2015
JHON VS. PETER, AGOO PET.

How Old Are You

Thanks
# 2  
Old 07-14-2015
Hello lxdorney,

Following may help you in same but as per your given pattern of line [A.B. No. T-8346, January 01, 2015 ].
Code:
 awk '{if($0 ~ /^ \[A\.B/){gsub(/\[|\]/,X,$0);sub(/\,/,"<br>",$0)};print;next} 1'  Input_file

Output will be as follows.
Code:
  A.B. No. T-8346<br> January 01, 2015
JHON VS. PETER, AGOO PET.
How Old Are You

Thanks,
R. Singh
# 3  
Old 07-14-2015
Please be way more careful when preparing specifications! Your desired output does not match the verbal spec.
Where have the opening and closing brackets gone in your output? Where's the comma after the pattern?

And, any attempt from your side?
# 4  
Old 07-15-2015
Yes that's what we want to achieve, thank you so much..
if you could explain little by little much better to help other as well

Thanks again
Last edited by lxdorney; 07-15-2015 at 03:01 AM..
# 5  
Old 07-15-2015
Hello lxdorney,

Following is the explanation for same, hope that helps you. Also please always do show us your efforts as we all are here to learn. You can hit thanks button present at bottom of threads to anyone to whom you want to thank or appreciate.
Code:
awk '{if($0 ~ /^ \[A\.B/){gsub(/\[|\]/,X,$0);sub(/\,/,"<br>",$0)};print;next} 1'  Input_file
 
if($0 ~ /^ \[A\.B/)            #### looking for condition where it matches line which is starting from [A.B
gsub(/\[|\]/,X,$0)             #### If above if condition is TRUE then substitute all matches of [ and ] characters in that matched line with NULL.
;sub(/\,/,"<br>",$0)           #### Then substitute first match of charcter , wth <br>
;print                         #### Do print operation to newly formed line includng changes in above steps
next                           #### Now don't do any further operaion and go to next line
1                              #### awk works on condition and operation method so when condition is TRUE do certain operations as mentioned by user.
                                    so by giving 1 we are making condition TRUE and then no action/operatin given by me to it will perform default action/operation
                                    which is printing the lines.

Hope above helps you. Enjoy learning.

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
lxdorney
# 6  
Old 07-15-2015
In current context, you can simplify like this also

Code:
[akshay@localhost tmp]$ cat file
 [A.B. No. T-8346, January 01, 2015 ]
JHON VS. PETER, AGOO PET.

How Old Are You
 [A.C. No. T-8346, January 01, 2015 ]
JHON VS. PETER, AGOO PET.

How Old Are You

If pattern found, then substitute first found comma with <br> and global substitution, +1 default action print line.
Code:
[akshay@localhost tmp]$ awk '(/^ \[A.B/ && sub(/,/,"<br>") && gsub(/[\[\]]/,""))+1' file

Code:
 A.B. No. T-8346<br> January 01, 2015 
JHON VS. PETER, AGOO PET.

How Old Are You
 [A.C. No. T-8346, January 01, 2015 ]
JHON VS. PETER, AGOO PET.

How Old Are You

This User Gave Thanks to Akshay Hegde For This Post:
lxdorney
# 7  
Old 07-15-2015
Quote:
Originally Posted by Akshay Hegde
... ... ...
Code:
[akshay@localhost tmp]$ awk '(/^ \[A.B/ && sub(/,/,"<br>") && gsub(/[\[\]]/,""))+1' file

... ... ...
Although the above works with some versions of awk, the standards say the only backslash escapes that are required to be recognized by awk are:\\, \/, \", \a, \b, \f, \n, \r, \t, and \v, and \d, \dd, and \ddd (where d is an octal digit). Anything else following a \ in a bracket expression produces undefined behavior.

In a bracket expression, if the first character inside the brackets (or immediately after the ^ in a non-matching list in a non-matching bracket expression) is a closing bracket, that closing bracket is a character in the list; not a terminator for the matching expression. And, inside a bracket expression, there is nothing special about an opening bracket except when it appears as the start of a collating symbol expression, the start of an equivalence class expression, or the start of a character class expression. So, two standard ways to specify an ERE containing a bracket expression matching the two characters [ and ] in awk are /[][]/ and "[][]".
These 2 Users Gave Thanks to Don Cragun For This Post:
Akshay Hegde lxdorney
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