While loop is causing ssh command to exit from script after first iteration.
I am trying to check multiple server's "uptime" in a loop over "ssh".
When I execute multiple ssh commands with hard coded servernames script is executing fine.
But when I pass server names using while loop, script is exiting after checking first server's status, why?
Code:
# serverList
serverA
serverB
serverC
Code:
# checkServerStatus.sh
#!/bin/bash
# This block got executed fine without exiting from script.
ssh serverA uptime
ssh serverB uptime
ssh serverC uptime
# This block is exiting from script after executing ssh once with serverA.
while read server; do
ssh $server uptime
done < serverList
Code:
>
# output
$> bash -xv ./test.sh
#!/bin/bash
ssh serverA uptime
+ ssh serverA uptime
04:38am up 39 days 0:23, 1 user, load average: 0.00, 0.02, 0.05
ssh serverB uptime
+ ssh serverB uptime
04:38am up 38 days 22:40, 0 users, load average: 0.01, 0.04, 0.05
ssh serverC uptime
+ ssh serverC uptime
04:38am up 39 days 5:47, 0 users, load average: 0.00, 0.01, 0.05
while read server; do
ssh $server uptime
done <serverList
+ read server
+ ssh serverA uptime
04:38am up 39 days 0:23, 1 user, load average: 0.00, 0.02, 0.05
+ read server
If I comment "ssh $server uptime" and simply print it "echo ssh $server uptime", while loop is not exiting.
How can I fix this or work around this?
Last edited by kchinnam; 07-13-2015 at 01:57 AM..
Reason: indentation
Don, usually I would be scared to try </dev/null(empty stuff), but I tried, its working,, how is it telling ssh not to use same file descriptor to read serverList?
Aia, changing file descriptor is not working for me..
Code:
#!/bin/bash
while read -u12 server; do
ssh $server uptime
done 12 < serverList
output:
./test.sh: line 4: syntax error near unexpected token `12'
ssh -n is working for my current script. But I do see myself using ssh in a interactive manner and enter passwords to remote server login.. in that case I guess while can't be an option..
Interestingly when I replaced while with for loop, its working fine.. since my input is simple I can afford, but this is not the right way for complex inputs.
Code:
for server in $(cat $serverList); do
ssh $server uptime
done
How can tell ssh not to read from serverList file? -u12 trick is not working on SuSE linux 11 I am using..
Last edited by kchinnam; 07-13-2015 at 05:07 AM..
Reason: clarifying
ssh - unless told otherwise - reads from stdin and empties the serverlist until EOF when used within the while loop. A for loop doesn't access stdin; there's the difference.
If you want to have interactive input as well as file input, you'll have to separate both streams, as Aia proposed using a different input file descriptor for the serverlist.
How can I separate file descriptor only for ssh without using "-n"?
I am using SuSE linux 11, "while read -u12 server; do" trick is not working.
I also tried "while read server <&10; do", its not working either.
---------- Post updated at 04:20 AM ---------- Previous update was at 04:13 AM ----------
I would propose this solution. Use a separate file descriptor for "while read", I picked 9 here(when for is not a choice :-).
Code:
#!/bin/bash
while read server <&9; do
ssh $server uptime
done 9<zlist
The 12< trick IS working, as long as you comply the the correct syntax (no space!).
And, <&12 would duplicate stdin from fd 12 which is assumedly unassigned and thus "doesn't work". Had you assigned fd 12 to some file prior to using it, it would have worked.
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