Process a file for line count using for loop in awk


 
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# 1  
Old 07-06-2015
Process a file for line count using for loop in awk

Hi,

I have a file with contents

Quote:
Name = abc
HPScore = 6.00
HMScore = 7.99
HSScore = 7.73
Pre avg = 2.90
Pre bind ene =1.09
Name = djhf
HPScore = 16.00
HMScore = 17.99
HSScore = 17.73
Pre avg = 21.90
Pre bind ene =111.09
Name = sgs
HPScore = 12.00
HMScore = 43.99
HSScore = 72.73
Pre avg = 25.90
Pre bind ene =14.09
Name = lksf
HPScore = 61.00
HMScore = 34.99
HSScore = 1.73
Pre avg = 34.90
Pre bind ene =12.0
.
.
.
.
So what I have to do is
Quote:
Name = abc HPScore = 6.00 HMScore = 7.99 HSScore = 7.73 Pre avg = 2.90 Pre bind ene =1.09
Name = djhf HPScore = 16.00 HMScore = 17.99 HSScore = 17.73 Pre avg = 21.90 Pre bind ene =111.09
. . . . .
. . . . .
In short, break the file after every 6 lines and then truncate new line to tab for these 6 lines.
I am not able to execute the for loop in awk properly.
The idea is something like this:
less file| awk '{for .... {if ((nr>=1) && (nr<=6)) print $0}}'| tr "\n" "\t"

Can someone help me on this
# 2  
Old 07-06-2015
Hi Rossi,

Use below code:

Code:
  
 awk '{A[(NR-1)%6]=A[(NR-1)%6]$0" ";next}END{for(i in A)print A[i]}' fileName

# 3  
Old 07-06-2015
Hi Shilpi,

the output from your code is

Quote:
HMScore = 7.99 HMScore = 17.99 HMScore = 43.99 HMScore = 34.99
HSScore = 7.73 HSScore = 17.73 HSScore = 72.73 HSScore = 1.73
Pre avg = 2.90 Pre avg = 21.90 Pre avg = 25.90 Pre avg = 34.90
Pre bind ene =1.09 Pre bind ene =111.09 Pre bind ene =14.09 Pre bind ene =12.0
Name = abc Name = djhf Name = sgs Name = lksf
HPScore = 6.00 HPScore = 16.00 HPScore = 12.00 HPScore = 61.00
I am looking for something else.

But thanks, it might be useful for other problems.
# 4  
Old 07-06-2015
Try this:
Code:
awk 'NR % 6 {printf $0 FS; next}1'  file

This User Gave Thanks to Franklin52 For This Post:
# 5  
Old 07-06-2015
Code:
$ perl -pe 's/\n/ / unless ($. % 6) == 0' file
Name = abc HPScore = 6.00 HMScore = 7.99 HSScore = 7.73 Pre avg = 2.90 Pre bind ene =1.09
Name = djhf HPScore = 16.00 HMScore = 17.99 HSScore = 17.73 Pre avg = 21.90 Pre bind ene =111.09
Name = sgs HPScore = 12.00 HMScore = 43.99 HSScore = 72.73 Pre avg = 25.90 Pre bind ene =14.09
Name = lksf HPScore = 61.00 HMScore = 34.99 HSScore = 1.73 Pre avg = 34.90 Pre bind ene =12.0

or the reverse
Code:
perl -pe 's/\n/ / if ($. % 6)' file

This User Gave Thanks to Aia For This Post:
# 6  
Old 07-06-2015
Thanks Fraklin and Aia,

It works, I will try to understand the logic of doing these tasks in the future.
# 7  
Old 07-06-2015
Quote:
Originally Posted by rossi
Thanks Fraklin and Aia,

It works, I will try to understand the logic of doing these tasks in the future.
Code:
awk 'NR % 6 {printf $0 FS; next}1'  file

NR % 6: evaluates if the line number is a multiple of 6. if evaluates as non-zero line must be truncated. 0 skip this action and go to the final action (final 1)
printf $0 FS;: display the current record + a Field Separator (in this case default space)
next: continue to the next record and do not evaluate anything else
1: it can be any non-zero, and makes awk to use the default action of print $0, if you get to this point


Code:
perl -pe 's/\n/ / unless ($. % 6) == 0' file

-pe: print all lines
s/\n/ / unless ($. % 6) == 0: substitute the end of line for space unless that the line number is a multiple of 6
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