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Script Shell Extract substring

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# 1  
Old 06-27-2015
Script Shell Extract substring
Hi all,

Please, i'd like to extract string just before '.fr'.
Here is some lines of my file:

Code:
g-82.text.text1.fr.worker1
g-xx.yyyyyy.zzzz.fr.worker2

i'd like to extract this text:

Code:
g-82.text.text1
g-xx.yyyyyy.zzzz

Please, which command i have to use in my script shell ?

Thank you much.
Best Regards.
# 2  
Old 06-27-2015
Hi, if its bash, this should work fine:
Code:
while read input
do  echo "${input/.fr.*}"
done<file

Prints:
Code:
g-82.text.text1
g-xx.yyyyyy.zzzz

hth

EDIT:
And to illustrate the substitution:
Code:
PATTERN=".fr."
VARIABLE="g-xx.yyyyyy.zzzz.fr.worker2"
echo "${VARIABLE/$PATTERN}"

Using a single / in ${VARIABLE}, removes the following pattern, including *?. expansion, unless quoted or escaped
Using two // will replace the the 1nd pattern string with the 2nd pattern string.
Example:
Code:
echo "${VARIABLE/$SEARCH/$REPLACE}"

However, this will only apply to the first found occourence!
Last edited by sea; 06-27-2015 at 12:51 PM..
This User Gave Thanks to sea For This Post:
chercheur111
# 3  
Old 06-27-2015
And, with any POSIX-conforming shell (e.g., ash, bash, dash, ksh, etc.) you could use:
Code:
while read -r input
do	echo "${input%.fr.*}"
done<file

or with sed:
Code:
sed 's/[.]fr[.].*//' file

or with awk:
Code:
awk '{sub(/[.]fr[.].*/, "")}1' file

or ...
This User Gave Thanks to Don Cragun For This Post:
chercheur111
# 4  
Old 06-27-2015
You could use :

Code:
sed 's/\(.fr.*\)//g' file

HTH
# 5  
Old 06-27-2015
Quote:
Originally Posted by Mannu2525
You could use :

Code:
sed 's/\(.fr.*\)//g' file

HTH
No.

With an input line like:
Code:
g-xx.Africa.zzzz.fr.worker3

the above sed command would produce the output:
Code:
g-xx.

instead of the requested:
Code:
g-xx.Africa.zzzz

In a filename matching pattern, . matches a period. But in a basic regular expression (which is what is used in sed), an unadorned . matches any single character.
# 6  
Old 06-27-2015
Quote:
Originally Posted by Mannu2525
You could use :
Code:
sed 's/\(.fr.*\)//g' file

HTH
A few things you might want think about:
\(\): you are telling to capture the matched part. Since you are not using it, it is a waste of effort.
g: matching as many times as possible in a line, is not the intention in this case.
# 7  
Old 06-27-2015
How about

Code:
$ cat > tmp
g-82.text.text1.fr.worker1
g-xx.yyyyyy.zzzz.fr.worker2


$ awk -F".fr" '{print $1}' tmp
g-82.text.text1
g-xx.yyyyyy.zzzz
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