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How I can find the last file created and move it to a directory?

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Top Forums Shell Programming and Scripting How I can find the last file created and move it to a directory?
# 1  
Old 06-17-2015
How I can find the last file created and move it to a directory?
I have this situation
Code:
 /u03/app/banjobs> ls -ltr icg*


        82 Jun 12 10:37 iicgorldi_2419186.log
  56810484 Jun 17 10:35 icgorldi_2421592.xml
      2859 Jun 17 10:35 icgorldi_2421592.lis
-      125 Jun 17 10:35 icgorldi_2421592.log
      82 Jun 12 10:37 iicgorldi_2419187.log
   56810484 Jun 17 10:35 icgorldi_2421597.xml
     2859 Jun 17 10:35 icgorldi_2421597.lis
  1 banjobs  jobsub       125 Jun 17 10:35 icgorldi_2421597.log
2421597.xml

I need to grab the last XML file created
rename and move to a directory the number (2421597) change every time the process run, I need to write a shl script to do that...The process that generates the file is schedule to run 3 times a day, so three different files are created
with a different number like:
Code:
 icgorldi_2421597.xml
icgorldi_2421598.xml
icgorldi_2421599.xml

The number is a sequence but it its share by other processes, so this file is not necessary in a sequence 97..9..99 the number is random..
Thank you

Thank you
Moderator's Comments:
Mod Comment Please use CODE tags when displaying sample input, sample output, and sample code segments.
Last edited by Don Cragun; 06-17-2015 at 09:38 PM.. Reason: Add CODE tags.
# 2  
Old 06-17-2015
Where are you having problems in your script? Could you post it?
# 3  
Old 06-17-2015
Quote:
Originally Posted by Bernardo Jarami
I have this situation
Code:
 /u03/app/banjobs> ls -ltr icg*


        82 Jun 12 10:37 iicgorldi_2419186.log
  56810484 Jun 17 10:35 icgorldi_2421592.xml
      2859 Jun 17 10:35 icgorldi_2421592.lis
-      125 Jun 17 10:35 icgorldi_2421592.log
      82 Jun 12 10:37 iicgorldi_2419187.log
   56810484 Jun 17 10:35 icgorldi_2421597.xml
     2859 Jun 17 10:35 icgorldi_2421597.lis
  1 banjobs  jobsub       125 Jun 17 10:35 icgorldi_2421597.log
2421597.xml

I need to grab the last XML file created
rename and move to a directory the number (2421597) change every time the process run, I need to write a shl script to do that...The process that generates the file is schedule to run 3 times a day, so three different files are created
with a different number like:
Code:
 icgorldi_2421597.xml
icgorldi_2421598.xml
icgorldi_2421599.xml

The number is a sequence but it its share by other processes, so this file is not necessary in a sequence 97..9..99 the number is random..
Thank you

Thank you
Moderator's Comments:
Mod Comment Please use CODE tags when displaying sample input, sample output, and sample code segments.
There are some very strange things going on here:
  1. The output from ls -ltr icg* should never give you files with names that do not start with the string icg.
  2. There are fields missing that should appear in output produced with the -l option.
  3. The fields produced by a given invocation of ls should have all fields aligned.
  4. The output from ls -ltr icg* should give you lines in reverse sorted order of the last modification times of the listed files; not dates that jump back and forth between June 12 and June 17.
  5. If you are looking for xml files why, why are you using ls -ltr icg* instead of ls -ltr *.xml? And, if you're just looking for filenames, why are you using the -l option?
  6. There are no ls options on most UNIX and Linux system filesystems to print file creation times. The ls -t option gives you a list of files sorted by the last file modification timestamp (not the file creation timestamp; most filesystems don't have a file creation timestamp).
  7. Where did the last line that you show as your output come from? It appears to just be a filename in a completely different file naming format than the other files in the directory and has none of the fields one would expect in long listing format?
# 4  
Old 06-18-2015
I do understand those commands, my problem is that you can have more than one file with the extension xml something like this
icgorldi_2421592.xml
icgorldi_2421593.xml
importi_2421592.xml
inform_2421592.xml

so I need a command where I can use the combination of icgorldi and xml to extract the last file created in the directory, remember the number between icgorldi_XXXX.xml changes every time the process run and create the file
I can't use ls -ltr xml* because there others files in the directory with the xml extension...
Hope this is clear
# 5  
Old 06-18-2015
How about ls icgorli*.xml, sort it, head it, and write the result to a file for later comparison?
This User Gave Thanks to RudiC For This Post:
Bernardo Jarami
# 6  
Old 06-18-2015
I'm still not clear as to what you are trying to accomplish.

But, assuming all of the tags are 7 digits long (as in icgorldi_2421593.xml), I don't see why:
Code:
ls -r icgorldi_*.xml | head -n 1

won't work to give you the XML file you want with the highest tag number and why
Code:
ls -t icgorldi_*.xml | head -n 1

won't work to give you the most recently modified XML file you want.

Won't one of these do what you want?
# 7  
Old 06-18-2015
This work
Code:
 s -r icgorldi_*.xml | head -n 1

what I am trying to do is to save that file in a variable
something like this
Code:
fn=$(ls -ltr  icgorldi*.xml | tail -1)

then I need to
rename the file (try this does not work)
Code:
rn $f icgorldi_06191015.xml

and not sure this will work since I haven't been able to rename
Code:
scp icgorldi_06191015.xml jostle:icgorldi_201601.xml

Last edited by Bernardo Jarami; 06-18-2015 at 10:43 PM..
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