Extract filename from a given string


 
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# 1  
Old 06-14-2015
Extract filename from a given string

I want to extract the filename from a string.

This is how I have the rawdata ina file


/home/sid/ftp/testing/abc.txt
/home/sid/ftp/tested/testing/def.txt
/home/sid/sftp/date/misc/hij.txt


i want a script which would provide me an output like this

Directory Filename
/home/sid/ftp/ abc.txt
/home/sid/ftp/tested/testing def.txt
/home/sid/sftp/date/misc hij.txt

All help appreciated.
# 2  
Old 06-14-2015
Quote:
Originally Posted by sidnow
I want to extract the filename from a string.

This is how I have the rawdata ina file


/home/sid/ftp/testing/abc.txt
/home/sid/ftp/tested/testing/def.txt
/home/sid/sftp/date/misc/hij.txt


i want a script which would provide me an output like this

Directory Filename
/home/sid/ftp/ abc.txt
/home/sid/ftp/tested/testing def.txt
/home/sid/sftp/date/misc hij.txt

All help appreciated.
Actually, you can help yourself, if you want. Look at this example:
Code:
file_path="/home/sid/ftp/tested/testing/def.txt"

echo ${file_path%/*} # this will display the directory path
/home/sid/ftp/tested/testing

echo ${file_path##*/} # this will display the file name without path
def.txt

Set up a loop with each absolute path and you have your script.
# 3  
Old 06-14-2015
When I put it in a loop it said bad substitution

This is the code

Code:
for i in `cat filename`
do
echo ${$i%/*} echo ${$i##*/}
done

It gave this error

Code:
bash: echo ${file_path%/*}:bad substitution

# 4  
Old 06-14-2015
Quote:
Originally Posted by sidnow
When I put it in a loop it said bad substitution

This is the code

Code:
for i in `cat filename`
do
echo ${$i%/*}; echo ${$i##*/}
done

It gave this error

Code:
bash: echo ${file_path%/*}:bad substitution

That was a good try, but it has a couple syntax errors.
Remove the red `$' and add the red `;'

However, that would display path and file in two different lines.
Modify as:

Code:
for i in `cat filename`
do
    printf "%s %s\n" ${i%/*} ${i##*/}
done


Last edited by Aia; 06-14-2015 at 08:22 PM..
This User Gave Thanks to Aia For This Post:
# 5  
Old 06-14-2015
Quote:
Originally Posted by Aia
That was a good try, but it has a couple syntax errors.
Remove the red `$' and add the red `;'

Brilliant Aia! It worked, thanks
# 6  
Old 06-14-2015
You can also use basename and the dirname to get the output
basename /tmp/abc.txt will give abc.txt
dirname /tmp/abc.txt will give /tmp
This User Gave Thanks to Khanaza For This Post:
# 7  
Old 06-15-2015
Quote:
Originally Posted by Aia
That was a good try, but it has a couple syntax errors.
Remove the red `$' and add the red `;'

However, that would display path and file in two different lines.
Modify as:

Code:
for i in `cat filename`
do
    printf "%s %s\n" ${i%/*} ${i##*/}
done


That is almost almost always the wrong way ro read the contents of a file. Not only is cat unnecssary but it will break your script if any lines contain whitespace or other pathological characters. It should be:

Code:
while read i
do
    printf "%s %s\n" "${i%/*}" "${i##*/}" ## note the quotes!
done < "$filename"

This User Gave Thanks to cfajohnson For This Post:
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