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Assigning a variable

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# 1  
Old 05-05-2015
Assigning a variable
I have a date column as 06302015 but I need to have variable which extracts 063015.

Am trying something like below but it is not assigning

Please let me know if am missing something. Thanks in advance.


################################

Code:
 #!/usr/bin/ksh
 
DT=06302015

 DT_ETL= echo "$DT" | cut -c1,2,3,4,7,8
 
EXTENSION="$DT_ETL"
  
 exit 0

################################
Last edited by Don Cragun; 05-06-2015 at 03:55 AM.. Reason: Add CODE tags.
# 2  
Old 05-06-2015
1. Avoid spaces around =

2. DT_ETL=$(echo "$DT" | cut -c1,2,3,4,7,8)
# 3  
Old 05-06-2015
First: CODE tags are VERY important. Without them, we couldn't see that you didn't have the #! on the 1st line of your script at the start of the line. With the #! following a space, it is just a comment and your script will be run by the default shell on your system; not /usr/bin/ksh.

And, if you're using the Korn shell (or any shell that performs the variable expansions required by the POSIX standards), you can run this faster using shell expansions instead of invoking an external utility (cut):
Code:
#!/usr/bin/ksh

DT=06302015
mmdd=${DT%????}
yy=${DT#??????}
EXTENSION="$mmdd$yy"
printf '%s\n' "$EXTENSION"
exit 0

which prints:
Code:
063015

instead of just setting a variable that can't be used after your script exits.
# 4  
Old 05-06-2015
You could also use
Code:
printf "%s\n" ${DT:0:4}${DT:6:2}
063015

# 5  
Old 05-06-2015
Quote:
Originally Posted by RudiC
You could also use
Code:
printf "%s\n" ${DT:0:4}${DT:6:2}
063015

With bash or a 1993 or later ksh; yes. But, the substring extraction parameter expansions are not required by the standards and do not appear in nearly as many shells as the ${var#pattern} and ${var%pattern} expansions.
# 6  
Old 05-06-2015
Hi All,

Thanks for the solutions.

Am able to extract the expected value but not able to assign to another variable. When I assign to another variable it becomes blank.

Even I tried with printf and it is also not working.

Code:
#!/usr/bin/ksh

DT=06302015

DT_ETL=$(echo "$DT" | cut -c1,2,3,4,7,8) 

EXTENSION="$DT_ETL"

exit 0

Output:

Code:
ksh -x test.ksh 06302015
+ DT=06302015
+ echo 06302015
+ cut -c1,2,3,4,7,8
+ 063015
+ DT_ETL=
+ EXTENSION=

Last edited by Don Cragun; 05-06-2015 at 04:14 PM.. Reason: Change ICODE tags to CODE tags.
# 7  
Old 05-06-2015
Difficult to believe ...
Code:
DT=06302015
+ DT=06302015
DT_ETL=$(echo "$DT" | cut -c1,2,3,4,7,8) 
echo "$DT" | cut -c1,2,3,4,7,8
++ echo 06302015
++ cut -c1,2,3,4,7,8
+ DT_ETL=063015

Are you sure you're showing the entire unmodified code snippet?
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