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How to remove certain character strings with awk?

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# 1  
Old 04-03-2015
How to remove certain character strings with awk?

Hi all,

I need to remove DBPATH= and /db from the string below using awk (or sed, as it also exists on the machine).


Desired output:

Thank you!

Last edited by rbatte1; 06-27-2016 at 05:47 AM.. Reason: Code tags
# 2  
Old 04-03-2015
Hello Ejianu,

Following may help you in same.
echo "DBPATH=/some/path/database/db" | awk '{sub(/.*=/,X,$0);print}'

R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
# 3  
Old 04-03-2015

Thank you for your prompt response. Unfortunately I get the following:

>echo "DBPATH=/some/path/database/db" | awk '{sub(/.*=/,X,$0);print}'
awk: syntax error near line 1
awk: illegal statement near line 1

# 4  
Old 04-03-2015
Hello ejianu,

On a Solaris/SunOS system, change awkto /usr/xpg4/bin/awk , /usr/xpg6/bin/awk, or nawk.

R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
# 5  
Old 04-03-2015

Thank you! You are correct, I am using a Solaris OS.

Using nawk and /usr/xpg4/bin/awk I get the following, which is closer to what I need, but I still get /db at the end. How can I remove the /db also?

>echo "DBPATH=/some/path/database/db" | nawk '{sub(/.*=/,X,$0);print}'

>echo "DBPATH=/some/path/database/db" | /usr/xpg4/bin/awk '{sub(/.*=/,X,$0);print}'

>echo "DBPATH=/some/path/database/db" | /usr/xpg6/bin/awk '{sub(/.*=/,X,$0);print}'
ksh: /usr/xpg6/bin/awk:  not found

# 6  
Old 04-03-2015
Hello ejianu,

Please try following(sorry I didn't see you don't need db also).
echo "DBPATH=/some/path/database/db" | nawk '{sub(/.*=/,X,$0);match($0,/\/.*\//);print substr($0,RSTART,RLENGTH-1)}'

R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
# 7  
Old 04-03-2015
It works. Thank you!

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