sed - remove begin of line up to the third and including occurence of character


 
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# 8  
Old 03-26-2015
Wouldn't the thread title suggest/imply the first s(ubstitute) command to be anchored with ^ ?
# 9  
Old 03-26-2015
Quote:
Originally Posted by RudiC
Wouldn't the thread title suggest/imply the first s(ubstitute) command to be anchored with ^ ?
That may well be true. The specification in post #1 and the title don't quite match. If we look at it closely, the description in post #1 can be interpreted several ways. It could also be interpreted to mean that instead of using $ as the delimiter, the first character on each input line is the delimiter for that line (and $ was just an example).

And, no sample input and expected output is provided.

Maybe jcdole will clarify the requirements so we'll all know what is really wanted.
# 10  
Old 03-28-2015
Just another idea, take a char which does not occur in your file (here for example "µ" ) and use it as a stop mark.
One advantage is that it can be used with string as delimiter.

Code:
$ echo fhdsjk123fjdksfj123gjfdklgjdf123jfdkslgfdsl123 | sed 's/123/µ/3;s/.*µ//'
jfdkslgfdsl123

These 2 Users Gave Thanks to ctsgnb For This Post:
# 11  
Old 03-30-2015
This is an interesting idea!
The stop mark can even be a new line
Code:
echo fhdsjk123fjdksfj123gjfdklgjdf123jfdkslgfdsl123 | sed 's/123/\
/3;s/.*\n//'

Quote:
jfdkslgfdsl123
In the original problem the delimiter was a $
Code:
sed 's/\$/\
/3;s/.*\n//' file


Last edited by MadeInGermany; 03-30-2015 at 07:35 AM..
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