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Needs perl script - pick right file name

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# 1  
Old 03-19-2015
Needs perl script - pick right file name
Hi.,

I need in perl type ...where this is an example :

assume a directory has 3 files namely:

Code:
file1_1445566_201501022.txt
file1_1445566_201502024.txt
file1_1445566_201503009.txt

where ,after second underscore, the number is in YYYYMMDD time-stamp format, I need perl script to pick up the file if the file name with time-stamp is latest, especially pick only - file1_1445566_201503009.txt


Thanks in advance
Last edited by rbatte1; 03-19-2015 at 02:53 PM.. Reason: Added CODE & ICODE tags for clarity
# 2  
Old 03-19-2015
You have naturally age sorted files by using a good file name standard.

Do you need to feed this into perl from a shell script or actually get perl to choose.


What have you tried so far?



Regards,
Robin
# 3  
Old 03-19-2015
want to write in perl scripting...not shellscript.
# 4  
Old 03-20-2015
Code:
$
$
$ ls -1 *.txt
file1_1445566_20140905.txt
file1_1445566_20140916.txt
file1_1445566_20140924.txt
file1_1445566_20141120.txt
file1_1445566_20141127.txt
file1_1445566_20141130.txt
file1_1445566_20141201.txt
file1_1445566_20150122.txt
file1_1445566_20150210.txt
file1_1445566_20150311.txt
$
$ perl -le 'foreach $file (glob "./*.txt") {
                ($ts = $file) =~ s/.*_(\d+)\..*$/$1/;
                $latest_file = $file if $ts > $prev_ts;
                $prev_ts = $ts;
            }
            END { print $latest_file }
           '
./file1_1445566_20150311.txt
$
$
$

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