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awk - how to pass varible

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# 1  
Old 03-17-2015
IBM awk - how to pass varible
I want to pass variable to below awk statement
Code:
awk  '/abc123/{x=NR+1}(NR<=x){print}' sftp_log_20150317.log

I tried -v like below, but its not working. Please help!!!
Code:
awk -v var1="abc123" '/var1/{x=NR+1}(NR<=x){print}' sftp_log_20150317.log

Input file is:
sftp_log_20150317.log

Code:
Interactive mode on.
Passive mode on.
mput abc123? 227 Entering Passive Mode (10,87,148,57,136,63)
150 Opening data connection for abc123.
226 Transfer complete.
248 bytes sent in 0.007882 seconds (30.73 Kbytes/s)
local: abc123 remote: abc123
221 Goodbye.

# 2  
Old 03-17-2015
You passed variable successfully, try like this

Code:
awk -v var1="abc123" '$0 ~ var1{x=NR+1}(NR<=x){print}' sftp_log_20150317.log

This User Gave Thanks to Akshay Hegde For This Post:
vegasluxor
# 3  
Old 03-17-2015
Expected out put is as below:

Code:
awk '/abc123/{x=NR+1}(NR<=x){print}'  sftp_log_INDB_20150317.log

Code:
mput abc123? 227 Entering Passive Mode (10,87,148,57,136,63)
150 Opening data connection for abc123.
226 Transfer complete.
local: abc123 remote: abc123
221 Goodbye.

It is searching for abc123 string and printing lines which has abc123 and also one more extra line.

---------- Post updated at 07:17 AM ---------- Previous update was at 07:15 AM ----------

Thanks!! It worked Smilie
# 4  
Old 03-17-2015
.
We can pass variable to Awk, refer link
path="xyzabc"

Code:
awk -v dir="$path" '{print $4 " " $3 " " dir}'

HTML Code:
http://exceptiongeek.com/questions/question/1/How-to-use-shell-variables-in-awk-script
Last edited by Scrutinizer; 03-17-2015 at 02:38 PM.. Reason: code tags
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