Shell Programming and Scripting

I'm glad it is working for you, but please consider the following comments...

Note that if #!/path/to/interpreter does not appear at the start of the 1st line in your file (with no leading spaces or tabs), your script will be run by whatever the system you're on uses as a default; not by the interpreter you list in this comment (/bin/ksh in this example).

If you get into the habit of using consistent indentation for all of your code blocks, you will save yourself MANY headaches in the future when you are trying to figure out why some line of code isn't running when you thought it would, and it will make debugging much easier when the shell tells you have a missing ), }, done, esac, or fi.

And, using awk to get the filename extension out of a string variable is a very slow, expensive way to perform a standard shell variable expansion. Try changing:

Code:

    if [ "$parent_dir" = "$dir" ]
    then    printf 'File "%s" not found.\n' "$file"
    ext=`echo ${file} | awk -F"." '{ print ($2) }'`
    cat /data/test/recept/EON/default/default.$ext
     exit 0
    fi

to:

Code:

    if [ "$parent_dir" = "$dir" ]
    then
        printf 'File "%s" not found.\n' "$file"
        cat /data/test/recept/EON/default/default."${file##*.}"
        exit 0
    fi