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Looping over output of 'ls'

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# 1  
Old 02-23-2015
Looping over output of 'ls'


I have some output from 'ls' command and I want to loop over the output in a bash script. What would be a good way to go about it?

For example, if the output of the ls command gives me 'prefix1 prefix2 prefix3', how can I set a loop that will iterate over these?

many thanks!
# 2  
Old 02-23-2015
#while (( 1 ))
        echo "--------------------------"
        sleep ${1}

./ 30 "ls -l"

ctrl-C to stop
# 3  
Old 02-23-2015
for i in `ls`; do <desired_command> $i; done

Moderator's Comments:
Mod Comment
Please wrap all code, files input & output/errors in CODE tags.
It makes them far easier to read and preserves multiple spaces which can be very important.

Last edited by rbatte1; 02-24-2015 at 09:04 AM..
# 4  
Old 02-24-2015
Originally Posted by ikable
for i in `ls`; do <desired_command> $i; done

Not necessary to use ls:
for i in *; do echo "$i"; done

# 5  
Old 02-25-2015
It's also not necessary to quote your $i element.
# 6  
Old 02-25-2015
Originally Posted by ikable
It's also not necessary to quote your $i element.
$i should be wrapped in double quotes to avoid field splitting or other interpretations by the shell. If there are files with spaces for example, they will break your script..

Last edited by Scrutinizer; 02-25-2015 at 03:08 PM..
This User Gave Thanks to Scrutinizer For This Post:

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