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sed match exactly and delete


 
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# 1  
Old 02-18-2015
sed match exactly and delete

I am using following sed rule to delete 2 lines after a pattern match inclusive.

Code:
[root@server ~]# cat /tmp/temp.txt
dns.com
11
22
mydns.com
11
22
dns.com.au
11
22
LAST LINE
[root@server ~]# cat  /tmp/temp.txt | sed -e '/dns.com/,+2d'

LAST LINE

I just need to remove lines below dns.com only and NOT below other domains. The rule I am using deletes lines below mydns.com and dns.com.au
# 2  
Old 02-18-2015
Code:
sed '/^dns\.com$/ {p;N;N;d;}' /tmp/temp.txt

This User Gave Thanks to MadeInGermany For This Post:
# 3  
Old 02-18-2015
Try:
Code:
sed '/^dns\.com$/,+2d' /tmp/temp.txt

This User Gave Thanks to radoulov For This Post:
# 4  
Old 02-18-2015
Anchor the pattern :
Code:
sed -e '/^dns.com$/,+2d' file
mydns.com
11
22
dns.com.au
11
22
LAST LINE

This User Gave Thanks to RudiC For This Post:
# 5  
Old 02-18-2015
Following up on MadeInGermany's more standard sed solution,
I suppose the OP needs something like this:
Code:
sed '/^dns\.com$/ {N;N;d;}' /tmp/temp.txt


Last edited by radoulov; 02-18-2015 at 06:32 AM..
This User Gave Thanks to radoulov For This Post:
# 6  
Old 02-18-2015
Thank you all. It works pefectly.

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