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How to print values that are greater than 0.1 in at least 80% of the samples?

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Top Forums Shell Programming and Scripting How to print values that are greater than 0.1 in at least 80% of the samples?
# 29  
Old 04-07-2015
Sorry for the headers. For the group counts, I didn't consider that one line can have several groups fulfilling the requirements. Try
Code:
awk     'NR==1  {for (i=1; i<=NF; i++)  {GRCNT[$i]++
                                         if (!GRMIN[$i]) GRMIN[$i]=i+1
                                         GRMAX[$i]=i+1
                                        }
                 if (debug) for (i in GRCNT) print "Verteilung: ", $1, i, GRCNT[i], GRMIN[i], GRMAX[i]
                 print
                }
         NR==2  {print}
         NR>2   {for (gc in GRCNT)      {TOT[gc]=0
                                         for (i=GRMIN[gc];i<=GRMAX[gc];i++)
                                                {TOT[gc]+=($i>0.1)
                                                 if (debug) print $1, gc, i, $i, ($i>0.1)
                                                }
                                        }
                }
                {for (gc in TOT)        {if (debug) print NR, $1, gc, GRCNT[gc], TOT[gc]
                                         if (TOT[gc] >= GRCNT[gc] * 0.8) {Pr=1; CNT[gc]++}
                                        }
                 if (Pr) {print; Pr=0}
                }
         END    {for (c in CNT) print c, CNT[c]}
        ' file
.
.
.
g4_x 2
g1_lpx 1
gn_m 2
g2_edfj 1

This User Gave Thanks to RudiC For This Post:
quincyjones
# 30  
Old 04-08-2015
this will be the final request. is it possible to print no.of groups and no.of rows in common from thesame input above. great thanks.


output

Code:
no.of groups    no.of rows in common
0       0
1       3
2       2
3       0
4       0
5       0

# 31  
Old 04-08-2015
Not clear. Please elaborate.
# 32  
Old 04-08-2015
Hope its clear .... please let me know if not. thanks

input
Code:
        g1_lpx  g1_lpx  g1_lpx  g1_lpx  g2_edfj g2_edfj g2_edfj g3_pp   g3_pp   g3_pp   g3_pp   g4_x    g4_x    gn_m    gn_m    gn_m    gn_m
        qwe100  qwe101  qwe133  qwe44   qweq33  qweq44  qwe77   qwexc2  qwe34   qwe55   qwe77   qwe99   qwe88   qwer5   qwer6   qwer8   qwer9
l1      1       1       1       0       0       0       0       0       0       0       0       1       1       0       0       0       0
l2      0       0       0       1       1       1       1       0       0       0       0       1       1       0       0       0       0
l3      0       0       0       0       0       0       0       0       0       0       0       0       0       1       1       1       1
l4      0       0       0       0       0       0       0       0       0       0       0       0       0       0.3     0.3     0.3     0.3
l5      0.4     0.4     0.4     0.4     0       0       0       0       0       0       0       0       0       0       0       0       0

output description
Quote:
0 (none of the groups)
1 (1 of the 5 groups g1_lpx or g2_edfj or g3_pp or g4_x or gn_m)
2 (2 of the 5 groups)
3 (3 of the 5 groups)
4 (4 of the 5 groups)
5 (5 of the 5 groups)

calculate how many of keys (l1 or l2 or l3 or l4 or l5) satisfy the condition 80% in groups 1 or 2 or 3 or 4 or 5

therefore

no.of groups no.of rows in common
0 0
1 3 (l3/l4/l5)
2 2(l1/l2)
3 0
4 0
5 0
# 33  
Old 04-09-2015
Code:
awk     'NR==1  {for (i=1; i<=NF; i++)  {if (!($i in GRCNT)) GR++
                                         GRCNT[$i]++
                                         if (!GRMIN[$i]) GRMIN[$i]=i+1
                                         GRMAX[$i]=i+1
                                        }
                 if (debug) for (i in GRCNT) print "Verteilung: ", $1, i, GRCNT[i], GRMIN[i], GRMAX[i]
                 print
                }
         NR==2  {print}
         NR>2   {for (gc in GRCNT)      {TOT[gc]=0
                                         for (i=GRMIN[gc];i<=GRMAX[gc];i++)
                                                {TOT[gc]+=($i>0.1)
                                                 if (debug) print $1, gc, i, $i, ($i>0.1)
                                                }
                                        }
                }
                {for (gc in TOT)        {if (debug) print NR, $1, gc, GRCNT[gc], TOT[gc]
                                         if (TOT[gc] >= GRCNT[gc] * 0.8) {Pr=1; GCNT[gc]++; LCNT[$1]++}
                                        }
                 if (Pr) {print; Pr=0}
                }
         END    {for (g in GCNT) print g, GCNT[g]
                 for (l in LCNT) {print l, LCNT[l]
                                  NCNT[LCNT[l]]++
                                 }
                 print "no. grp\tno.of rows in common"
                 for (i=0; i<=GR; i++) print i "\t" NCNT[i]+0
                }
        ' file
        g1_lpx  g1_lpx  g1_lpx  g1_lpx  g2_edfj g2_edfj g2_edfj g3_pp   g3_pp   g3_pp   g3_pp   g4_x    g4_x    gn_m    gn_m    gn_m    gn_m
        qwe100  qwe101  qwe133  qwe44   qweq33  qweq44  qwe77   qwexc2  qwe34   qwe55   qwe77   qwe99   qwe88   qwer5   qwer6   qwer8   qwer9
l1      1       1       1       0       0       0       0       0       0       0       0       1       1       0       0       0       0
l2      0       0       0       1       1       1       1       0       0       0       0       1       1       0       0       0       0
l3      0       0       0       0       0       0       0       0       0       0       0       0       0       1       1       1       1
l4      0       0       0       0       0       0       0       0       0       0       0       0       0       0.3     0.3     0.3     0.3
l5      0.4     0.4     0.4     0.4     0       0       0       0       0       0       0       0       0       0       0       0       0
g4_x 2
g1_lpx 1
gn_m 2
g2_edfj 1
l1 1
l2 2
l3 1
l4 1
l5 1
no. grp no.of rows in common
0       0
1       4
2       1
3       0
4       0
5       0

Please be aware that l1 only has one group satisfying the condition!
This User Gave Thanks to RudiC For This Post:
quincyjones
# 34  
Old 04-09-2015
Quote:
Please be aware that l1 only has one group satisfying the condition!
but l1 satisfy the condition in 2 groups i.e, g1_lpx and g4_x.
0,1,2,3,4,5 doest represent l1, l2, l3, l4, l5. they represent groups (g1_lpx.....gn_m)
# 35  
Old 04-09-2015
g1_lpx has three out of four which is 75% not exceeding the required 80%. What do you mean by
Quote:
0,1,2,3,4,5 doest represent l1, l2, l3, l4, l5. they represent groups (g1_lpx.....gn_m)
and how does it relate to my last proposal?
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