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Reduce the number of lines by using Array

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# 1  
Old 01-08-2015
Reduce the number of lines by using Array
I have the following code to count the number of how many times the name occurred in one file. The code is working fine and the output is exactly what I want. The problem is the real code has more than 50 names in function listname which cause function name to have more than 50 case ,and function setname more than 50 lines.

is there a way to rewrite function name and function setname in short code? someone told me I can use Array but not sure how. My goal is to reduce the number of lines.

Code:
function listname {

echo "List of Name:-"

  echo "1-Kim    2-Lee     3-Jack     4-Sam"
  echo "5-Nick    6-Smith"

name;
 }

function name {
  echo "Which name ou want to change?"
        read iname
 
        case $iname in
        1 ) echo "Kim"

               read -p "Enter Kim: " Kim
               echo "Kim=($Kim)"
        ;;
        2 ) echo "Lee"

               read -p "Enter Lee: " Lee
               echo "Lee=($Lee)"
     
        ;;

        3 ) echo "Jack"

               read -p "Enter Jack: " Jack
               echo "Jack=($Jack)"
        ;;

        4 ) echo "Sam"

               read -p "Enter Sam: " Sam
               echo "Sam=($Sam)"
        ;;
        5 ) echo "Nick"

               read -p "Enter Nick: " Nick
               echo "Nick=($Nick)"
        ;;
        6 ) echo "Smith"

               read -p "Enter Smith: " Smith
               echo "Smith=($Smith)"

        ;;
   
        * ) echo "You did not enter a number"
                echo "between 1 and 6." 

esac
 echo "Do you want another change?"
 read anothchang
     case $anothchang in
        [yY] | [yY][Ee][Ss] )
        listname;
             ;;
       [nN] | [nN][Oo] )
        setname;

}


function setname {      
               [ -z "$Kim" ] && Kim="cat /tmp/list | grep -c Kim"
               [ -z "$Lee" ] && Lee="cat /tmp/list | grep -c Lee"
               [ -z "$Jack" ] && Jack="cat /tmp/list | grep -c Jack"
               [ -z "$Sam" ] && Sam="cat /tmp/list | grep -c Sam"
               [ -z "$Nick" ] && Nick="cat /tmp/list | grep -c Nick"
               [ -z "$Smith" ] && Smith="cat /tmp/list | grep -c Smith"
output;
    }

 function output {

 echo "Kim ($Kim)  
   Lee($Lee) 
   Jack($Jack) 
   Sam($Sam) 
   Nick($Nick)   
   Smith($Smith)"
  }
echo "Hello"
listname;

# 2  
Old 01-08-2015
I don't think above code is working fine. Having corrected several logical and syntactical errors, I'm still not sure I understand what you are doing - you have a list of six name constants, and six variables named identically. The latter are used to hold either a character string alternative name to be read from stdin (user terminal) or, if that is missing, an integer word count for, again, text constants. In the end, if an alternate name is entered, you output that, otherwise the word count for the respective text constant in a /tmp file. On top, your recursive use of functions is somewhat unorthodox.

Assuming you have a recent bash, and names in a file like
Code:
Kim
Lee
Jack
Sam
Nick
Smith

, try this
Code:
mapfile -tO1 ORIG <file
mapfile -tO1 NAMES <file
select NAME in ${NAMES[@]}
        do [ $REPLY -eq 0 ] && break
           read -p "Enter ${NAMES[$REPLY]} " NAMES[$REPLY]
        done
for i in ${!ORIG[@]}
        do printf "%s(" ${ORIG[$i]}
           [ "${ORIG[$i]}" == "${NAMES[$i]}" ] && 
                printf "%s)\n" $(grep -c ${NAMES[$i]} /tmp/list) ||
                printf "%s)\n" "${NAMES[$i]}"
        done

to reproduce what I think you want to achieve.
This User Gave Thanks to RudiC For This Post:
samsan
# 3  
Old 01-08-2015
The use of numbers suggests you want to use a simple vector array, but why not skip the numbers and use just names and an associative array?
This User Gave Thanks to DGPickett For This Post:
samsan
# 4  
Old 01-08-2015
Might be an option if the OP's intentions were clear...
This User Gave Thanks to RudiC For This Post:
samsan
# 5  
Old 01-08-2015
i apologize for the misunderstanding , this is not the really code. I just wrote the above code to gave you in idea of what I am trying to do.
I fixed the code above , and now should run. Let say here is what inside my list file:-

Code:
cat list 
Sam
Sam
Kim
Sam
Kim
Jack
Nick
Nick
Smith
Smith

when I run the code :-

Code:
List of Name:-
1-Kim    2-Lee     3-Jack     4-Sam
5-Nick    6-Smith
Which name ou want to change?
1
Kim
Enter Kim: 23
Kim=(23)
Kim (23)  
   Lee(0) 
   Jack(1) 
   Sam(3) 
   Nick(2)   
   Smith(2)

The code is running fine , I just want it to know if there is any way to rewrite it in short way.

here is the updated code
Code:

function listname {

echo "List of Name:-"

  echo "1-Kim    2-Lee     3-Jack     4-Sam"
  echo "5-Nick    6-Smith"

name;
 }

function name {
  echo "Which name ou want to change?"
        read iname

        case $iname in
        1 ) echo "Kim"

               read -p "Enter Kim: " Kim
               echo "Kim=($Kim)"
        ;;
        2 ) echo "Lee"

               read -p "Enter Lee: " Lee
               echo "Lee=($Lee)"

        ;;

        3 ) echo "Jack"

               read -p "Enter Jack: " Jack
               echo "Jack=($Jack)"
        ;;

        4 ) echo "Sam"

               read -p "Enter Sam: " Sam
               echo "Sam=($Sam)"
        ;;
        5 ) echo "Nick"

               read -p "Enter Nick: " Nick
               echo "Nick=($Nick)"
        ;;
        6 ) echo "Smith"

               read -p "Enter Smith: " Smith
               echo "Smith=($Smith)"

        ;;

        * ) echo "You did not enter a number"
                echo "between 1 and 6."

esac
setname;
}


function setname {
               [ -z "$Kim" ] && Kim=`cat list | grep -c Kim`
               [ -z "$Lee" ] && Lee=`cat list | grep -c Lee`
               [ -z "$Jack" ] && Jack=`cat list | grep -c Jack`
               [ -z "$Sam" ] && Sam=`cat list | grep -c Sam`
               [ -z "$Nick" ] && Nick=`cat list | grep -c Nick`
               [ -z "$Smith" ] && Smith=`cat list | grep -c Smith`
output;
    }

 function output {

 echo "Kim ($Kim)
   Lee($Lee)
   Jack($Jack)
   Sam($Sam)
   Nick($Nick)
   Smith($Smith)"
  }
echo "Hello"
listname;

# 6  
Old 01-09-2015
Here is something to get started, to chew on Smilie

Code:
#!/bin/bash
#
#
#	Variables
#
	declare -A AGE				# Create an associative array
	NAMES="Kim Lee Jack Sam Nick Smith"	# List with names
#
#	Fill the array
#
	select name in Back $NAMES;do		# Select an entry of the list NAMES
		[[ $name = Back ]] && break	# Exit the select-loop / break out
		
		echo "Hello $name, what is your age?"
		read age
		AGE[$name]=$age			# Set the arrays entry '$name' to value '$age'
	done
#
#	Output the content
#
	for n in $NAMES
	do
		echo "$n is ${AGE[$n]} years old"
	done
	echo "Have a nice day :)"

Hope this helps
This User Gave Thanks to sea For This Post:
samsan
# 7  
Old 01-09-2015
Thank you sea , it helped me with other code Smilie , but it is not what I am looking here
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