Help with modifying a filename


 
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# 1  
Old 11-01-2014
Help with modifying a filename

Hello,

I have a filename that looks like this:

Code:
ABC_96_20141031_041133.232468

I need to shorten only the "_2014" part of the filename to simply "_14" so the filename looks like:

Code:
ABC_96_141031_041133.232468

I have to do a search for this string because there are hundreds of files and the 96 after the ABC is a sequence number, so some files are like ABC_1_20141031, ABC_10_2014 and ABC_100_2014.

I can rename files and take out or add a prefix and suffix but struggle when it comes to changing anything in the middle. Smilie

How can I accomplish this please?

Last edited by bbbngowc; 11-01-2014 at 08:55 PM..
# 2  
Old 11-01-2014
Code:
ls * | perl -lne 'print "$& $_" if s/(^[A-Z]{3}_\d+_)\d\d(\d\d.*$)/$1$2/'

If you like the result then change the red part to rename the files:
Code:
ls * | perl -lne 'rename $&, $_ if s/(^[A-Z]{3}_\d+_)\d\d(\d\d.*$)/$1$2/'


Last edited by Aia; 11-01-2014 at 09:57 PM.. Reason: Explicit mention to rename
# 3  
Old 11-02-2014
Try this:
Code:
ls *_*_2014*_*.* | while read original
do
 new=$(echo "$original" | awk -F_ 'BEGIN{OFS="_"}{gsub(/^20/,"",$3); print}')
 echo "$original" "$new"
done

or even this, utilizing bash's built-ins:
Code:
ls *_*_2014*_*.* | while read original
do
#disassembling sample file ABC_96_20141031_041133.232468
 piece1=${original##*_} # piece1 now holding 041133.232468
 piece2=${original%_*}  # piece2 now holding ABC_96_20141031
 piece3=${piece2%_*}    # piece3 now holding ABC_96
 piece4=${piece2##*_}   # piece4 now holding 20141031
 piece5=${piece4:2}     # piece5 now holding 141031
#reassembling
 echo "$original" "$piece3"_"$piece5"_"$piece1"
done

In both cases you'll need to substitute echo with mv to perform the actual rename process.
# 4  
Old 11-02-2014
An another solution, with sed


Code:
ls * | while read file
do 
mv $file $(echo $file | sed 's/\(ABC_\)\([0-9]*_\)\(2014\)\(.*\)/\1\214\4/')
done

# 5  
Old 11-02-2014
Wow! Those are some interesting ways. I accomplished it use the following:

Code:
ls -1 XV4_* | awk '{print("mv "$1 " " $1)}' | sed 's/_2014/_14/2' > rename_files.txt

Then made the rename_files.txt executable and ran it. I'm going to have to study up on some of the ways suggested, but the good thing with this site is, should I need this method again, just come look.

Thanks everyone!
# 6  
Old 11-02-2014
That works, but this will be smaller/faster/less consumptive:
Code:
ls -1 XV4_* | awk '{X=$1; sub(/_2014/,"_14",X); print "mv", $1,X}'
or
ls -1 XV4_*| sed  's/\(.*\)/mv \1 \1/;s/_2014/_14/2'

Did you consider to just use (recent) shell builtins
Code:
for FN in ABC_*; do echo mv "$FN" "${FN/_2014/_14}"; done

?
# 7  
Old 11-02-2014
Try:
Code:
for f in *_*_20*_*.*
do
  [ -f "$f" ] && mv -- "$f" "${f%_*_*}_${f#*_*_20}"
done


Last edited by Scrutinizer; 11-02-2014 at 02:36 PM..
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