How to run scripts parallely inside shell script?


 
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# 1  
Old 10-14-2014
How to run scripts parallely inside shell script?

Hi ,

I have 4 scripts example script1,script2,script3,script4 .

I have to run script1,script2 and script3 parallely since this 3 scripts dont have dependencies .
Once script1,script2 and script3 got completed successfully , I have to trigger script4.

Can someone help me on this how to right script for this!!!

Thanks,
Vinoth
# 2  
Old 10-14-2014
What have you tried so far?
What scripting langauge?
# 3  
Old 10-14-2014
Quote:
Originally Posted by vinothsekark
Hi ,

I have 4 scripts example script1,script2,script3,script4 .

I have to run script1,script2 and script3 parallely since this 3 scripts dont have dependencies .
Once script1,script2 and script3 got completed successfully , I have to trigger script4.

Can someone help me on this how to right script for this!!!

Thanks,
Vinoth
Hi vinothsekark,

You can try as follows, not tested though.

Code:
#!/bin/bash
./script1 &
./script2 &
./script3 &
Q=1
 
While (Q==1)
do
PID1=`ps -ef | grep -v grep | grep "script1"`
PID2=`ps -ef | grep -v grep | grep "script2"`
PID3=`ps -ef | grep -v grep | grep "script3"`
 
 
sleep 10 ## you can give here number of seconds as per you wish as not sure about how long scripts wil be taking to complete##
 
if [[ $PID1 == "" && $PID2 == "" && $PID3 == "" ]]
then
       ./script 4
       Q=0
else
       Q=1
fi
done

kindly try it in a non live environment as it is not tested and let us know.

EDIT: Sorry sea seems we have updated the post on same time didn't see your question.

Thanks,
R. Singh

Last edited by RavinderSingh13; 10-14-2014 at 02:37 AM.. Reason: Adding sorry, as sea asked a question to OP+edited space thanks to sea
# 4  
Old 10-14-2014
@ RavinderSingh: No issues.
There is a space and numbering issue with $PID =="" -> $PID3 == ""
This User Gave Thanks to sea For This Post:
# 5  
Old 10-14-2014
The same could be achieved with
Code:
./script1 &
./script2 &
./script3 &
wait
./script4

However this wil also not test the return codes of the background scripts..
The challenge is to reliably capture those before script 4 can continue...

Something like this perhaps (not tested)
Code:
wrong=0
./script1 & ./script2 & ./script3 &
for job in $(jobs -p)
do
  wait $job || wrong=$((wrong+1))
done
if [ $wrong = 0 ]; then
  ./script4
fi


Last edited by Scrutinizer; 10-15-2014 at 01:24 AM..
This User Gave Thanks to Scrutinizer For This Post:
# 6  
Old 10-14-2014
The capture whether the script is running or not - is easy, at least when compared to the challenge transporting the exit value out of the subshell to that this handler script knows it, which script has exited with which exit code.

I would have a solution for this at hand, but I'm afraid it works only with 1 background process at a time (that is pseudo-copied to below example).

Either way, it forces you to send a more complex command in the background process, adapt to all 3 files.
Code:
( ./script1 ; printf $? > ./script1_ret  )

Then catch the result of those ./script[1-3]_ret files within a loop, and it should be fine.

Hope this helps

EDIT:
Just for the challenge I've written a script, but not going to post until TO has posted his efforts.

Last edited by rbatte1; 10-14-2014 at 07:15 AM.. Reason: Spelling
# 7  
Old 10-14-2014
Came up with this alternative with bash, ksh93 or zsh, using the named pipes of process substitution.
Code:
{
  read rc1 <&3
  read rc2 <&4
  read rc3 <&5
} 3< <(./script1 >/dev/null 2>&1; echo $?) \
  4< <(./script2 >/dev/null 2>&1; echo $?) \
  5< <(./script3 >/dev/null 2>&1; echo $?) 
if [ $rc1 = 0 ] && [ $rc2 = 0 ] && [ $rc3 = 0 ] ; then
  ./script4
fi


Last edited by Scrutinizer; 10-15-2014 at 01:24 AM..
This User Gave Thanks to Scrutinizer For This Post:
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