Shell Programming and Scripting

Hi there,

I am new to shell scripting and have been struggling with this example.

I have an input variable that looks like that:
FILELIST="100_*_123.txt"

that will produce a list of files if you use
ls ${FILELIST}

The output looks like 100_EN_123.txt 100_FR_123.txt

I am building HTML code out of it and need the list to be separated by html tags like this:

<p>100_EN_123.txt </p><p>100_FR_123.txt</p>

This is what I have so far except that it does not actually do the replacements I need:

Code:

echo "<p>"
ls ${FILELIST}| sed 's/\n/</p><p>/g'
echo "</p>"

I also searched and found a perl way of doing it but it gives an error that I don't know how to fix:

Code:

echo "<p>"
ls ${FILELIST}| perl -pe 's/\n/$1</p><p>/'
echo "</p>"

There must be something very simple that I am not getting. Please help if you can.

Instead of echo, try using printf, so you can force the linebreaks where you want them:

eg:

Code:

for F in ${FILELIST};do
    printf "<p>$F</p>\n"
done

hth

Try:

Code:

printf "<p>%s</p>" $FILELIST
printf "\n"

Try

Code:

ls $FILELIST| awk '{for (i=1; i<=NF; i++) $i="<p>"$i"</p>"}1' RS= OFS=

THANK YOU!

All solutions worked like a charm!

The solution suggested by Scrutinizer is the simplest I think.

I guess I need to read on printf command to understand how it works.

It was my first post and I did not expect 3 replies in so short time.

Thank you again.