Assigning multiple variables in ksh script


 
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# 8  
Old 09-24-2014
Here is part of the script that is giving me issues...

Code:
printf "Enter Account name: "
read Answer

        #Print blanket cancel working directory and process id
        echo BLANKET CANCEL:
        echo $(date +'%c')
        ps -e -o pid,args | grep "phantom EORD.BLANKET.CANCEL" | grep -v grep | while read pid command
        do
                ln=`procwdx $pid`
                echo "$ln" | grep -q "${Answer}" && echo "$ln" && ps -ef | grep $pid | grep -v grep | sed -e 's/^[ \t]*//'
        done
	echo


Script results:
Code:
Enter Account name: NAIB

BLANKET CANCEL:
Wed Sep 24 08:26:59 EDT 2014
8585430:        /home/HKUNAIB/
root  8585430        1   0   Sep 04      -  0:04 phantom EORD.BLANKET.CANCEL
8978610:        /home/NAIB/
root  8978610        1   0   Sep 16      -  0:19 phantom EORD.BLANKET.CANCEL

In this script I dont want it to display "HKUNAIB". Please advise
# 9  
Old 09-24-2014
You can use:
Code:
grep -w

---------- Post updated at 07:53 AM ---------- Previous update was at 07:38 AM ----------

There's stuff in your script which can be changed such as redundant grep's etc.

Just looking at the pertinent points though, I would imagine that you would want something like this in replace of your first two lines (the printf and read):

Code:
max=5; set --
while [[ ($# -eq 0) || ($# -gt $max) ]] ; do
        print "Please enter no more than $max account names: "
        read -r input; set -- ${input} 
        IFS='|'; RE="$*"
done

Then instead of:
Code:
grep -q "${Answer}"

You can use:
Code:
egrep -qw "${RE}"


Last edited by pilnet101; 09-24-2014 at 10:03 AM..
# 10  
Old 09-24-2014
Looks good now. Thank you all!!!! Smilie
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