How find Linux version from command line?


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# 1  
How find Linux version from command line?

Hi,

I am looking to extract linux version from /etc/*-release file.

I am specifically tring to avoid use of awk command here. would be great if can do done via sed or grep command.

Red Hat Enterprise Linux Server release 6.5 (Tikanga)

output must be 6

regards,
Litu
# 2  
Hello Litu,

Kindly use the code tags for commands and codes which you are using in the posts, also you can review your post before click on Submit Reply by clicking on Preview Post. Following may be helpful for you.

Code:
awk '{print $(NF-1)}' /etc/redhat-release

This should show the version of Linux Server release.

Thanks,
R. Singh
# 3  
thanks for the reply. But we are trying to avoid use of awk command. can we do the same using grep, sed or cut command.
# 4  
Hello Litu,

Following sed solution may help you.

Code:
sed 's/[[:alpha:]]//g;s/[[:space:]]//g' filename

EDIT: Adding more solutions for same.

Code:
cut -f7 -d " " /etc/redhat-release | cut -c1
 
cut -f7 -d " " /etc/redhat-release | cut -f1 -d"."

Thanks,
R. Singh

Last edited by RavinderSingh13; 09-01-2014 at 09:52 AM.. Reason: Added filename + added more solutions with cut now
This User Gave Thanks to RavinderSingh13 For This Post:
# 5  
Both the codes give you 6 as the output
Code:
rev /etc/redhat-release | cut -f2 -d ' ' | rev | cut -f1 -d '.'

of
Code:
cut -f1 -d '.' /etc/redhat-release | rev | cut -f1 -d ' ' | rev

---------- Post updated at 07:54 AM ---------- Previous update was at 07:49 AM ----------

sed solution
Code:
sed 's/[^[:digit:]]*\([[:digit:]]*\)\..*/\1/' /etc/redhat-release


Last edited by SriniShoo; 09-01-2014 at 10:01 AM.. Reason: missed sed, thanks to Ravinder
# 6  
Posted by SriniShoo:

Quote:
Both the codes give you 6 as the output


Code:
rev /etc/redhat-release | cut -f2 -d ' ' | rev | cut -f1 -d '.'

of


Code:
cut -f1 -d '.' /etc/redhat-release | rev | cut -f1 -d ' ' | rev
Hello SriniShoo,

I am not sure why you are using rev here, I guess we can esaily do it with cut and sed.


EDIT: Also you have missed sed while giving sed solutions.
Quote:
Both the codes give you 6 as the output

Code:
rev /etc/redhat-release | cut -f2 -d ' ' | rev | cut -f1 -d '.'

of


Code:
cut -f1 -d '.' /etc/redhat-release | rev | cut -f1 -d ' ' | rev

---------- Post updated at 07:54 AM ---------- Previous update was at 07:49 AM ----------

sed solution


Code:
's/[^[:digit:]]*\([[:digit:]]*\)\..*/\1/' /etc/redhat-release
Code:
sed 's/[^[:digit:]]*\([[:digit:]]*\)\..*/\1/' /etc/redhat-release

Thanks,
R. Singh
# 7  
thanks a lot R Singh...
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