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Shell Programming and Scripting

Passing parameter through file

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# 1  
Old 08-18-2014
Passing parameter through file
Hi ,

I am passing date parameter through file

my shell script testing.sh is

Code:
#set -x
#set -v
asd=$1
asd1=$2
echo $asd
echo $asd1

Passing parameter as below

sh testing.sh `cat file1.txt`

Output

Code:
cat file1.txt
'2014-08-18 17:18:07' '2014-08-18 16:10:01'

Code:
sh testing.sh `cat file1.txt`
"'2014-08-18
17:18:07'"

when i use

Code:
sh testing '2014-08-18 17:18:07' '2014-08-18 16:10:01'
2014-08-18 17:18:07
2014-08-18 16:10:01

This gives right output

How to pass the parameter by using output of file as input .
Last edited by kaushik02018; 08-18-2014 at 01:15 PM..
# 2  
Old 08-18-2014
As your input 2014-08-18 17:18:07 already contains space .. you are getting that ouput
I have added pipe delimeter to your input file
Code:
$ more file1.txt
'2014-08-18 17:18:07'|'2014-08-18 16:10:01'

try
Code:
testing.sh "`awk '{print $1}' FS='|' file1.txt`" "`awk '{print $2}' FS='|' file1.txt`"

output
Code:
'2014-08-18 17:18:07'
'2014-08-18 16:10:01'

OR you want ouput on one line
Code:
testing.sh "`cat file1.txt`"

Last edited by Makarand Dodmis; 08-18-2014 at 01:16 PM..
This User Gave Thanks to Makarand Dodmis For This Post:
kaushik02018
# 3  
Old 08-18-2014
awk works for me

Thanks
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