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Help with if condition

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# 1  
Old 08-04-2014
Help with if condition
o/p of my command is given below
Quote:
Release : 2014Q1
Branch : stabilization
BuildNumber : 2013
PNumber : 3
My requirement is

Code:
if Pnumber is 0 then

	stabilization.Build.2013

else

stabilization.PBuild.2013.3

Last edited by rbatte1; 08-04-2014 at 06:39 AM..
# 2  
Old 08-04-2014
What have you tried so far?
Where is that you got stuck?
# 3  
Old 08-04-2014
Dear nikhil jain,
I have a few to questions pose in response first:-
  • What have you tried so far?
  • What output/errors do you get?
  • What OS and version are you using?
  • What are your preferred tools? (C, shell, perl, awk, etc.)
  • What logical process have you considered? (to help steer us to follow what you are trying to achieve)
Most importantly, What have you tried so far?

There are probably many ways to achieve most tasks, so giving us an idea of your style and thoughts will help us guide you to an answer most suitable to you so you can adjust it to suit your needs in future.


We're all here to learn and getting the relevant information will help us all, and you have over 100 posts, so I'm sure you know how to ask a good question.



Regards,
Robin
# 4  
Old 08-04-2014
sorry for the whole lot of confusion,

Release : 2014Q1
Branch : stabilization
BuildNumber : 2013
PNumber : 3


Whenever Pnumber is other than 0 then i want it to display as stabilization.PBuild.2013.$PNumber i.e. the value whatever PNumber is having after delimiter ":"
in this case it is 3.
If PNumber : 0 then it should display as stabilization.Build.2013

Sorry Again.
# 5  
Old 08-04-2014
So, what have you tried so far and what errors do you get?

If the output you are showing us is the right detail but the wrong format, it would be useful to know how you are getting the output you have shared.

You know when you your car breaks down, do you just ring them and say "It doesn't work." can they diagnose and fix it without know what is really wrong or even seeing the car?


Please tell us:-
  • What have you tried so far?
  • What output/errors do you get?
  • What OS and version are you using?
  • What are your preferred tools? (C, shell, perl, awk, etc.)
  • What logical process have you considered? (to help steer us to follow what you are trying to achieve)
Most importantly, What have you tried so far?

There are probably many ways to achieve most tasks, so giving us an idea of your style and thoughts will help us guide you to an answer most suitable to you so you can adjust it to suit your needs in future.


We're all here to learn and getting the relevant information will help us all.




Regards,
Robin
# 6  
Old 08-04-2014
Code:
set -x
#find /opt/c/Com/depots -name "version.info" > a.txt
 
while read line
do
cat $line > detail.txt
var=`cat detail.txt|awk -F ":" '/PatchNumber/ {print $2}'`
if [ $var == "0" ]
then
echo "stabilization.Build.2013"
else
echo "stabilization.PatchBuild.2013.$var"
fi
done < a.txt

a.txt contains

/a/b/c/v.info
/d/e/f/v.info
...
...

v.info contains

Release : 2014Q1
Branch : stabilization
BuildNumber : 2013
PNumber : 3

but PNumber keeps changing based on v.info file
# 7  
Old 08-04-2014
I'm afraid your code snippet won't print either of your strings, as var will be empty (not "0"!) due to the wrong pattern: "PatchNumber" will not be found in v.info.
Should var contain any integer number, and with not too old a shell, try (no if [ ... ] needed)
Code:
VX=${var##0}; echo stabilization.${VX:+Patch}Build.2013${VX:+.}$VX
stabilization.Build.2013
stabilization.PatchBuild.2013.3

Last edited by RudiC; 08-04-2014 at 09:15 AM.. Reason: made it ##0 to remove ALL leading blanks in VX
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