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# 1  
Old 07-03-2014
Help with regular expression

Hi All

We have a file with statements like below
 . and so on

We want the word Anything after FROM<SPACE> and stop when the word Encounter Space.

Could some please help with a regular expression/sed with which I can achieve this?
 OUTPUT expected is


Last edited by vbe; 07-03-2014 at 10:56 AM..
# 2  
Old 07-03-2014
 awk '{match($0,/FROM (\w+\.\w+)/,a); print a[1]}' infile

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# 3  
Old 07-03-2014

kindly use the code tags for any commands or codes as per forum rules.
Also following code may help you in same.

awk -F"FROM " '{gsub(/[[:space:]].*/,X,$2); print $2}' File_name

Output will be as follows.


R. Singh
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# 4  
Old 07-03-2014

sed 's/.*FROM \([^ ][^ ]*\).*/\1/' file

awk '/FROM/ {getline;print;next}' RS=' ' file

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# 5  
Old 07-03-2014
sed -n 's/.*FROM \([^ ]*\).*/\1/p' file

sed '/.*FROM /!d; s///; s/ .*//' file

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# 6  
Old 07-04-2014
Thank you for your responses.

I tried its working as expected.

I need to get that inside awk, can I use SED?

Can I use awk inside awk?
# 7  
Old 07-04-2014
Yes, you can invoke sed inside awk, and yes, you can invoke awk inside awk; but there is very seldom any reason to do so.

You have already been shown several ways to do what you requested in your original post. So, I assume you must want to do something more than you have shown us.

Please explain what you're trying to do. Show us some sample input and what output you're trying to produce (using CODE tags). Show us the code you have tried and explain what it isn't doing that you want it to do.
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