PHP - Regex for matching string containing pattern but without pattern itself


 
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# 1  
Old 06-27-2014
PHP - Regex for matching string containing pattern but without pattern itself

The sample file:
Code:
dept1: user1,user2,user3
dept2: user4,user5,user6
dept3: user7,user8,user9

I want to match by '/^dept2.*/' but don't want to have substring 'dept2:' in output. How to compose such regex?
# 2  
Old 06-27-2014
Try:
Code:
awk '/^dept2/{print $2}' file

# 3  
Old 06-27-2014
Quote:
Originally Posted by bartus11
Try:
Code:
awk '/^dept2/{print $2}' file

I need to use it in php script. Calling awk from there sounds not good. Moreover i can split string into array and shift it, but i'd like to know regex-based solution just to extend my regex knowledge.
# 4  
Old 06-27-2014
What function are you using (if any), and are you passing it the whole file or 1 line at a time?
# 5  
Old 06-28-2014
Quote:
Originally Posted by CarloM
What function are you using (if any), and are you passing it the whole file or 1 line at a time?
I'm using preg_match_all('/(dept1.*|dept2.*|dept3.*)/i', $curl_out, $userarray1, REG_SET_ORDER);
$curl_out - is input multiline variable (curl execution)
$userarray1 - is output multiline array
# 6  
Old 06-28-2014
whether like this do you expect output to be ?

Code:
akshay@Aix:~$ php -r 'echo preg_replace("/dept.*: /","", "dept1: user1,user2,user3")."\n"; '
user1,user2,user3

Code:
akshay@Aix:~$ php -r '$var = spliti ("dept.*:", "dept1: user1,user2,user3"); print_r($var);'
Array
(
    [0] => 
    [1] =>  user1,user2,user3
)


Note : This function has been DEPRECATED as of PHP 5.3.0

Last edited by Akshay Hegde; 06-28-2014 at 01:58 PM..
# 7  
Old 06-28-2014
I don't have PHP handy at the moment, but try:
Code:
preg_match_all ('/^(dept1|dept2|dept3)(.*)$/im', $curl_out, $userarray1, PREG_PATTERN_ORDER);

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