Sed: printing lines AFTER pattern matching EXCLUDING the line containing the pattern

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# 1  
Old 06-04-2014
Sed: printing lines AFTER pattern matching EXCLUDING the line containing the pattern


I'm using the following code to extract the lines(and redirect them to a txt file) after the pattern match. But the output is inclusive of the line with pattern match.

Which option is to be used to exclude the line containing the pattern?

sed -n  '/Conn.*User/,$p' > consumers.txt

# 2  
Old 06-04-2014
awk '/Conn.*User/{p=1;next}p' consumers.txt

# 3  
Old 06-04-2014
To print line after pattern:

 sed -n '/pattern/{n;p;}' infile

# 4  
Old 06-04-2014
Originally Posted by Klashxx
To print line after pattern:

 sed -n '/pattern/{n;p;}' infile

This shows the immediate next line to the pattern. Not showing ALL the lines.
# 5  
Old 06-04-2014
sed -n '/pattern/,${/pattern/!p;}' file

(but this will delete all lines with /pattern/ from the output)

sed '1,/pattern/d' file

But this will give the wrong result if the pattern is on line 1

GNU sed:
sed '0,/pattern/d' file

Using awk:
awk 'p; /pattern/{p=1}' file

On Solaris use /usr/xpg4/bin/awk rather than awk

Last edited by Scrutinizer; 06-05-2014 at 07:09 AM..
# 6  
Old 06-04-2014
Does your server support the -A flag on grep? That might be a neater solution:-
grep -A10 pattern  file

Maybe I've missed the point. If you want all lines after a certain point, perhaps you could use grep to get the record number and then tail to get you the output you need:-

grep -n pattern  file|tr ":" " "|read line xxx       # Get the interesting line number
wc -l file | read total xxx                          # Get total lines
((readrecs=$total-$line))                            # Work out how many lines from end to read
tail -$readrecs   file

Do either of these help?

# 7  
Old 06-04-2014
In sed you need a loop:
sed -n '/pattern/{
b loop
}' file

---------- Post updated at 12:33 PM ---------- Previous update was at 12:22 PM ----------

BTW in sed you don't need to repeat a pattern on the same line:
sed -n '/pattern/,${//!p;}' file
sed -n '/pattern/ s//replacement/p' file

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