Zipping the files with data


 
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# 8  
Old 05-26-2014
Hi Don,

I don't know whether I made the requirements clear. Sorry if I woudln't have done it.

I have files
abc_1.csv
abc_2.csv
abc_3.csv

These files should be zipped into one file abc.zip

All the three files will have standard header a,b,c,d even though data is present or not.

Say for an example out of 3 files above one file abc_2.csv is not having the data it should not be added to zip file.

So under this scenario my zip file should contain only abc_1.csv, abc_3.csv

Thanks.
# 9  
Old 05-26-2014
Assuming that you're using a shell that recognizes basic POSIX shell constructs, you could try something like:
Code:
for i in a_cd_*.csv
do	if [ $(wc -l < "$i") -gt 1 ]
	then	printf "%s\n" "$i"
	fi
done | zip -@ a_cd

This zip utility is not covered by the standards and its options may vary from system to system. This was tested and works on Mac OS X.
This User Gave Thanks to Don Cragun For This Post:
# 10  
Old 05-26-2014
Don,

Thanks a lot for your help.

Code is working fine.

Thanks once again.
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