Shell Programming and Scripting

Hi All,

Am trying to print pervious lines of the pattern matched, I was able to print pattern matched and the required data but don't know how to get the pervious line.

Code:

 ifconfig -a | grep  10.118.67.33 | sed -e 's/^[[: :]]*//' -e 's/[[: :]]*$//' | awk '{FS=" "; print $6}'

output I get is the ipaddress ie,

Code:

 10.118.67.33

what am looking is how to get the pervious line of this ipaddress... can someone please help me on this.


Many thanks
Ops

The whole line before pattern?

Code:

ifconfig -a | awk '{a[++i]=$0;} /10.118.67.33/{print a[NR-1]}'

Thanks Aia. logic works perfectly. this what I was looking for and I was struggling to get pervious whole line.

Many Thank Again.