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sed and awk to insert a line after a para

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# 1  
Old 05-12-2014
Tools sed and awk to insert a line after a para
hi

I am having a file like this

##############################
Code:
mod1 ( a(ll) , b(
c), try(o) , oll(ll)
go(oo) , al(ll)
mm(al) , lpo(kka)
kka(oop) );

mod2 ( jj(ll) , c(
kk), try1q(o1) , ofll(lll)
gao(oo1) , ala(llaa)
mmf(adl) , lddpo(kkad)
kkda(oodp) );

##########################################

I want to match the regular expression line mod1 and mod2 in the file and insert a line

Code:
#####################
ak(kk) , akjj(ll) , aa(99k)

after the module ending before ));

Output file

Code:
mod1 ( a(ll) , b(
c), try(o) , oll(ll)
go(oo) , al(ll)
mm(al) , lpo(kka)
kka(oop) ,ak(kk) , akjj(ll) , aa(99k) );

mod2 ( jj(ll) , c(
kk), try1q(o1) , ofll(lll)
gao(oo1) , ala(llaa)
mmf(adl) , lddpo(kkad)
kkda(oodp) ,ak(kk) , akjj(ll) , aa(99k) );

##############################

I am using below command
Code:
sed '/mod1/a ak(kk) , akjj(ll) , aa(99k)' file1 
sed '/mod2/a ak(kk) , akjj(ll) , aa(99k)' file1

but it is appending text after match only

Please let me know how it can work
Last edited by Don Cragun; 05-12-2014 at 04:12 AM.. Reason: Change HTML tags to CODE tags.
# 2  
Old 05-12-2014
Code:
sed 's/;/ak(kk) , akjj(ll) , aa(99k);/g'

# 3  
Old 05-12-2014
regular expression match and insert line before ending the module
Thanks Protocomm

But this is a small section of the file
so I need to match with mod1 and mod2 regular expression and insert the line where those modules are ending before ));

Thanks
Kshitij
# 4  
Old 05-12-2014
Try:
Code:
awk '
$1 ~ /^mod[12]$/ {
	add = 1
}
add && /[)];/ {
	sub(/[)];/, ",ak(kk) , akjj(ll) , aa(99k) );")
	add = 0
}
1' file

If you want to use this on a Solaris/SunOS system, use /usr/xpg4/bin/awk or /usr/xpg6/bin/awk instead of just awk.
Last edited by Don Cragun; 05-12-2014 at 04:28 AM.. Reason: Simplify the awk script.
# 5  
Old 05-12-2014
Maybe you can prepend the stuff?
Code:
sed '
/mod1 (/ s//& ak(kk) , akjj(ll) , aa(99k) ,/
/mod2 (/ s//& ak(kk) , akjj(ll) , aa(99k) ,/
' file1

# 6  
Old 05-12-2014
Quote:
Originally Posted by Don Cragun
Try:
Code:
awk '
$1 ~ /^mod[12]$/ {
	add = 1
}
add && /[)];/ {
	sub(/[)];/, ",ak(kk) , akjj(ll) , aa(99k) );")
	add = 0
}
1' file

If you want to use this on a Solaris/SunOS system, use /usr/xpg4/bin/awk or /usr/xpg6/bin/awk instead of just awk.
Don Cragun,
I don't understand the working of the variable add ???
Could you explain please ?
if add is equal to 1 then you do sub ?
but why 1 && /[)];/ allow it ?

Thanx
# 7  
Old 05-12-2014
Probably you understand, if it becomes more explicit
Code:
( add==1 && /[)];/ ) { ... }

or
Code:
{ if ( add==1 && /[)];/ ) { ... }
}

NB && means AND
This User Gave Thanks to MadeInGermany For This Post:
protocomm
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