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Listing the file name and no of records in each files for the files created on a specific day

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Top Forums Shell Programming and Scripting Listing the file name and no of records in each files for the files created on a specific day
# 1  
Old 05-06-2014
Oracle Listing the file name and no of records in each files for the files created on a specific day
Hi,

I want to display the file names and the record count for the files in the 2nd column for the files created today.
i have written the below command which is listing the file names. but while piping the above command to the wc -l command
its not working for me.

Code:
ls -l --time-style='+%d/%m/%Y' | grep '06/05/2014' |  awk '{print $7}'

Need suggestion to get the file name and record count of the files.

Thanks
# 2  
Old 05-06-2014
try
Code:
for file in $(ls -ltr | grep "May  6" | awk '{print $9}');
do
 rc=`cat $file | wc -l`
 echo $file $rc
done

# 3  
Old 05-06-2014
Oracle
Thanks so much . But i want it in a command not using script. if possible.
# 4  
Old 05-06-2014
How about
Code:
find . -type f -mtime -1 -exec wc -l {} +

# 5  
Old 05-07-2014
Oracle
Thanks a lot Rudic. Its almost satisfied my requirement But along with the files created today it is also listing one more file which was created one day before.

Anyway thanks. I will explore more on -mtime and will get the solution.

Thanks for your time.
# 6  
Old 05-07-2014
Look into -mmin as well, and -daystart if available on your system.
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