Shell Programming and Scripting

hi,

I would like to exlcude certain files which starts with AUS from a directory while gzip the files but i need it in gzip command only

Code:

direct:
AUS1.tx
AUS2.txt
NZ1.txt

i want to gzip only NZ1.txt to NZ1.gz files starting with AUS should not be gzipped and i need it in gzip command only

loop through the list of files and gzip the ones you need - here is one way that is easy to understand:

Code:

cd /path/to/files
ls |
  while read fname
  do 
       echo $fname | grep -q '^AUS' 
       [ $?  -eq 0 ]  && continue  # skip AUS files
       gzip $fname
  done

hi is it possible without loop becoz this is will impact the performance becoz there are huge number of files in the directory with huge sizes

try

Code:

gzip NZ*

hi there will be other files other than NZ it was just an example i want to exclude only files starting with AUS using gzip command

create AUS.sh and run ./AUS.sh

Code:

for file in $(ls -ltr | grep ^- | grep -v "AUS" | awk '{print $9}');
do
gzip $file
done

Remember here loop is to only zip files one by one and not for any conditional check

One more way without looping

Code:

gzip `ls -ltr | grep ^- | grep -v "AUS" | awk '{print $9}'`

more short

Code:

gzip `ls | grep -v "AUS"`

Your regular expression is underspecified. The goal is to eliminate files beginning with AUS, but you are eliminating anything that contains AUS. A leading anchor is required.

Using find is a much better solution; it is just as efficient (if not more so) and is safe against exceeding ARG_MAX with a massive argument list:

Code:

find . -type f \! -name 'AUS*' -exec gzip {} +

Regards,
Alister

---------- Post updated at 09:39 AM ---------- Previous update was at 09:34 AM ----------

If the shell supports it, and if you're willing to risk the implosion, you can use:

Code:

gzip !(AUS*)

Regards,
Alister