Help with 'pwd' command

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Top Forums Shell Programming and Scripting Help with 'pwd' command
# 1  
Old 04-20-2014
Help with 'pwd' command

Dear all,
I am trying to use 'pwd' command in following way.
current_directory == /dirA/dirB/test/dirC

if [ current_directory_path has char == 'test' ]; then
do this

I am not sure how to pass this in command way. Please help!

thanking you,
# 2  
Old 04-20-2014

case $current_directory in
  ( *test* ) do this ;;

# 3  
Old 04-20-2014
Trying to use your logic.

# 4  
Old 04-20-2014
I don't understand. What do you mean by *char* test? test is a string ...
# 5  
Old 04-20-2014
You pass just 1 path to current_directory.
In that case your approach should be more like:

for curDIR in $(ls -d *);do
  case $curDIR in
    ( *test* ) echo this $curDIR contain 'test'  ;;


Last edited by sea; 04-20-2014 at 05:33 PM.. Reason: added asterix (*) to list
# 6  
Old 04-20-2014
If that's the case, I'd rather use $PWD instead.
# 7  
Old 04-20-2014
Thanks Radoulov and Sea,
However, it seems I am not using it efficiencly. Here is the piece of code
echo $var_path
for $var_path in $(ls -d); do
  case $var_path in
    ( *src* ) echo this $var_path contain 'src'  ;;

It complains about:
parse error near `$var_path'

What is wrong here?

thanks again,
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