Help with 'pwd' command


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# 1  
Help with 'pwd' command

Dear all,
I am trying to use 'pwd' command in following way.
Code:
current_directory == /dirA/dirB/test/dirC

if [ current_directory_path has char == 'test' ]; then
do this
fi

I am not sure how to pass this in command way. Please help!

thanking you,
emily
# 2  
Code:
current_directory=/dirA/dirB/test/dirC

case $current_directory in
  ( *test* ) do this ;;
esac

# 3  
Thanks,
Trying to use your logic.

Greetings.
emily
# 4  
I don't understand. What do you mean by *char* test? test is a string ...
# 5  
You pass just 1 path to current_directory.
In that case your approach should be more like:

Code:
for curDIR in $(ls -d *);do
  case $curDIR in
    ( *test* ) echo this $curDIR contain 'test'  ;;
  esac
done

hth

Last edited by sea; 04-20-2014 at 06:33 PM.. Reason: added asterix (*) to list
# 6  
If that's the case, I'd rather use $PWD instead.
# 7  
Thanks Radoulov and Sea,
However, it seems I am not using it efficiencly. Here is the piece of code
Code:
var_path=`pwd`
echo $var_path
for $var_path in $(ls -d); do
  case $var_path in
    ( *src* ) echo this $var_path contain 'src'  ;;
  esac
done

It complains about:
Code:
parse error near `$var_path'

What is wrong here?

thanks again,
emily
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