Help with 'pwd' command


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# 8  
Try:
Code:
var_path=$PWD
echo "$var_path"
case $var_path in
    ( *src* ) echo "this $var_path contains 'src'";;
esac

Or just:
Code:
case $PWD in
    ( *src* ) echo "this $PWD contains 'src'";;
esac


Last edited by radoulov; 04-20-2014 at 06:47 PM..
This User Gave Thanks to radoulov For This Post:
# 9  
Hi radoulov,
Thanks , it seem to be working.
However, when I changed it bit for my purpose..I guess, it need some more fixing...
Code:
var_path=$PWD
echo "$var_path"
case $var_path in
    ( *src* ) ini sqdModule ;;
esac

where ini sqdModule can be run only with directories having *src* in their path. Else, it will complain.

I wonder putting ini sqdModule straight ahead in the piece of code is right?

Greetings
# 10  
If src is allowed but not xsrc or srcx
Code:
case /$var_path/ in
( */src/* ) echo "$var_path consists of 'src'";;
esac

This User Gave Thanks to MadeInGermany For This Post:
# 11  
Thank you,
How shall I pass this as input once the condition of /src/ is satsified.
ini sqdModule

It should print alike on terminal for initialization of some environment.

Greetings.
emily
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