Aggregation of huge data

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# 8  
Old 04-07-2014
Hi Akshay,

I even removed the blank and tried it - still facing the same issue. Also I copied few records to a new file (Say 5 lines) and even then - it is occuring !



Command used:

 awk 'BEGIN { print "Z = 0;" } { sub(/-/, ""); print "Z += ",$1,";" } END { print "Z;" }' test.txt


Z = 0;
Z +=  21000000 ;
Z +=  3000 ;
Z +=  3000 ;
Z +=  670500 ;
Z +=  2963700 ;

To my knowledge the above stated output, the value of z should be incremented na ?

Kindly advise me on the same.


Last edited by Ravichander; 04-07-2014 at 03:56 AM..
# 9  
Old 04-07-2014
Three weeks ago I suggested the code:
awk -F'|' -v dqANDms='["-]' '
BEGIN {	f=156
NR > 2 {gsub(dqANDms, "", $f)
	printf("s+=%s\n",  $f)
END {	printf("s\n")
}' file | bc

in another thread (Aggregation of Huge files) where you wanted to process the 156th field instead of the 1st field, wanted to strip out double quote characters if any were present, and had two header lines in your input that were to be ignored. You said that when your input file contained 7 million records, my code didn't work; but you weren't able to show any input that caused it to produce the wrong result. Instead of answering requests to show sample input that caused suggested scripts provided to you to fail, you started this new thread.

Simplifying that code for the data you've presented here yields:
awk '
BEGIN {	printf("s=0\n")
{	sub(/-/, "")
	printf("s+=%s\n", $1)
END {	printf("s\n")
}' test.txt | bc

which, with the sample input you provided in message #8 in this thread produces the output:

which still looks like the correct result to me. If this isn't the result you wanted, what were you expecting?

If it matters, the output from awk that the above script feeds into bc is:

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