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Looking for an awk command to print strings only if substring is missing

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Top Forums Shell Programming and Scripting Looking for an awk command to print strings only if substring is missing
# 15  
Old 04-07-2014
Hi.

Changing the final grep in my solution to:
Code:
grep -A1 "interface"

produces:
Code:
 Results:
interface 1/1/1/1 move-group
     decription one one one one
--
interface 1/1/1/3 move-group
     decription one one one three

Where the removal of the separator line if desired is left as an exercise.

Best wishes ... cheers, drl
# 16  
Old 04-07-2014
Thank you for the input DRL, but I do not have that grep option A1 on my server.
# 17  
Old 04-07-2014
Just also print $2 and an empty line:
Code:
awk '/^interface/{print x}1' file |
awk '!/filter-shared 14/ && /move-group/{print $1; print $2; print x}' FS='\n' RS=

# 18  
Old 04-07-2014
Hi.
Quote:
Originally Posted by numele
Thank you for the input DRL, but I do not have that grep option A1 on my server.
There is a perl version of grep called peg available at: http://www.cpan.org/authors/id/A/AD/ADAVIES/peg-3.10 , so using peg -A1 "interface" in place of the grep produces:
Code:
 Results:
interface 1/1/1/1 move-group
     decription one one one one
--
interface 1/1/1/3 move-group
     decription one one one three

Best wishes ... cheers, drl
# 19  
Old 04-07-2014
Scrutinizer, your solution works but it is so slow. I have 4400 large files to process and the awk statement I had been using was very fast. If I could just get it to add the next line, it would be perfect.
Code:
nawk 'END {if (!ok) print r} /interface/ && /move-group/ {if (!ok) print r; r = $0; ok = x}/filter-shared 14/ {r = r RS $0; ok++}' inputfile

# 20  
Old 04-08-2014
Try:
Code:
nawk '/interface/&&/move-group/{if(s)print s; s=x; n=2} n-->0{s=s $0 ORS} /filter-shared 14/{s=x; n=0} END{if(s)print s}' file

Last edited by Scrutinizer; 04-08-2014 at 10:27 AM..
This User Gave Thanks to Scrutinizer For This Post:
numele
# 21  
Old 04-08-2014
Thank you Scrutinizer! You are Mr. AWK!
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