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Convert single column into multiple rows

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# 1  
Old 03-28-2014
Power Convert single column into multiple rows
Convert Single column to multiple rows
file a.txt contains data like below

Code:
Server=abc
Run=1
Tables=10
Sessions=16
Time=380
Jobs=5
Server=abc
Run=2
Tables=15
Sessions=16
Time=400
Jobs=5
Server=abc
Run=3
Tables=20
Sessions=16
Time=450
Jobs=5

I am interested in only printing following values, Server is the breaker for the columns


Code:
Server abc abc abc
Run 1 2 3
Tables 10 15 20
Time 380 400 450

I am thinking like

Code:
report=" Server Run Tables Time "
for i in $report 
do
cat a.txt | awk -v search="$i" -F"=" '/search/ {print $1 $2}'
done

How can I do this?
Last edited by sol_nov; 03-28-2014 at 01:03 PM.. Reason: wrong title
# 2  
Old 03-28-2014
Would this work

Code:
sort  a.txt | awk -F'=' 'BEGIN {l=null} {if($1 != l ) {l=$1; printf("\n%s ",$1)} else { printf("%s ",$2)}}'

# 3  
Old 03-28-2014
thanks, but it is skipping the first instance, and I would like only the one from the list
report=" Server Run Tables Time "


Code:
Jobs 5 5
Run 2 3
Server abc abc
Sessions 16 16
Tables 15 20

# 4  
Old 03-28-2014
Sorry, I don't understand. Are you saying you want it in that order?
# 5  
Old 03-28-2014
Yes, only those variables in the
report=" Server Run Tables Time "
# 6  
Old 03-28-2014
ok, I get it
Here you go

Code:
sort a.txt | awk -F'=' 'BEGIN {l=null} $1 ~ /Time|Server|Run|Tables/ {if($1 != l ) {l=$1; printf("\n%s ",$1)} else { printf("%s ",$2)}}'

This User Gave Thanks to linuxpenguin For This Post:
sol_nov
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